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3 years ago

What is 7x7+89 i want to know what the b is to

Mathematics

2 answers:

gogolik [260]3 years ago

7 0

Answer:

138

Step-by-step explanation:

According to PEMDAS (explains which operation you do first)

(Parentheses

Exponents

Multiplication or Division

Addition or Subtraction),

1. multiplication comes before addition

2. Even if it was 89+7x7, it would still be 7x7 first.

3. 7x7=49. Add it to 89 and you get 138

user100 [1]3 years ago

4 0

7x7+89
In PEMDAS multiplication comes first
49+89
Add (7x7) and 89
The answer is 138

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Find the area of the polygon WXYZ with its vertices at W(–3, –2), X(–3, 5), Y(2, 5), and Z(2, –2).

ki77a [65]

Answer:

The area of the polynomial is 35 square unit.

Step-by-step explanation:

It is given that area of the polygon WXYZ with its vertices at W(–3, –2), X(–3, 5), Y(2, 5), and Z(2, –2).

From the below graph it is noticed that the given polynomial is a rectangle with length 5 and width 7.

The distance formula

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Using the above formula we get,

$WX=7$

$XY=5$

$YZ=7$

$WZ=5$

The length of opposing sides are equal.

Using the Pythagoras theorem, the length of diagonal WY and XZ are

$WY=\sqrt{(WX)^2+(XY)^2}=\sqrt{7^2+5^2}=\sqrt{74}$

$XZ=\sqrt{(XY)^2+(YZ)^2}=\sqrt{5^2+7^2}=\sqrt{74}$

Since the length of the diagonal are same, therefore the given polygon is a rectangle.

The area of a rectangle is

$A=l\times w$

Where l is length and w is width.

The area of given polynomial is

$A=5\times 7$

$A=35$

Therefore the area of the polynomial is 35 square unit.

6 0

3 years ago

If a boy and a half can eat a hot dog and a half, in a minute and a half, how many hot dogs can six boys eat in six minutes?

Yanka [14]

SIx boys can eat seven (7) hotdogs in six (6) minutes.

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3 years ago

What is the sum of the infinite geometric series 9−6+4−83+...9-6+4-83+...??

vivado [14]

Successive terms have a common factor of $-\dfrac23$ , which means the $n$ th partial sum of the series can be written as

$S_n=9-6+4-\dfrac83+\cdots+9\left(-\dfrac23\right)^{n-1}$
$S_n=9\left(1+\left(-\dfrac23\right)^1+\left(-\dfrac23\right)^2+\left(-\dfrac23\right)^3+\cdots+\left(-\dfrac23\right)^{n-1}$

$\implies-\dfrac23S_n=9\left(\left(-\dfrac23\right)^1+\left(-\dfrac23\right)^2+\left(-\dfrac23\right)^3+\left(-\dfrac23\right)^4+\cdots+\left(-\dfrac23\right)^n\right)$

$\implies S_n-\left(-\dfrac23\right)S_n=9\left(1-\left(-\dfrac23\right)^n\right)$
$\dfrac53S_n=9\left(1-\left(-\dfrac23\right)^n\right)$
$S_n=\dfrac{27}5\left(1-\left(-\dfrac23\right)^n\right)$

As $n\to\infty$ , the geometric term vanishes, leaving you with

$S=\displaystyle\lim_{n\to\infty}S_n=\dfrac{27}5$

7 0

3 years ago

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nirvana33 [79]

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3 years ago

A leaky pool loses 2 1/4 inches of water eachday. Jermain and mildred are asking to determine the change in the amount of water

inessss [21]

Answer:

Over 5 days, the pool loses 11 $\frac{1}{4}$ inches of water.

Step-by-step explanation:

Since the leaky pool is losing water at a rate of 2 $\frac{1}{4}$ inches of water each day, than we can find the amount of water the pool has lost over 5 days, by either adding 2 $\frac{1}{4}$ five times, or just multiplying 2 $\frac{1}{4}$ by 5:

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So, the total amount of water lost over 5 days is 11 $\frac{1}{4}$ inches.

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3 years ago