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Lapatulllka [165]

3 years ago

7

Mario is tracking the progress of his plant's growth. After 4 days the plant was 5 cm high. 13 days later the plant was 18.5 cm

tall.
What is the rate of growth of the plant?
How tall was the plant when Mario planted it?
How tall will the plant be after 20 days?

1 answer:

igor_vitrenko [27]3 years ago

7 0

Answer:

sjdhdjdbdkendbdidjdnd

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A deck of cards contains RED cards numbered 1,2,3 and BLUE cards numbered 1,2,3,4,5,6. Let R be the event of drawing a red card,

Tatiana [17]

Answer:

e. R′

Step-by-step explanation:

Let the Sample Space be a universal set consisting of 3 red and 6 blue cards. Then the event of of getting 4 blue cards will be given

R complement = R` = Universal Set minus Red cards will give blue cards.

a. R OR O

It cannot be this option because we need 4 blue card

b. B AND O

It cannot be this choice as well because 4 is not odd.

c. R OR E

4 is even but we need blue

d. R AND O

Red and odd is again not required

e. R′ = It will give our required result.

f. E′= 4 is even if it is complemented it cannot be obtained and will be left out.

5 0

3 years ago

Please help me, will mark brainliest for correct answers.....

Alexandra [31]

Answer:

1. B) 5.7

2. A) 12

3. A) 11.4

4. A) 5.7

5. A) 16.2

6. A) 11.2

7. No, they do not form a right triangle

8. Yes, they do form a right triangle

Step-by-step explanation:

Extra tip: The hypotenuse has to be less than both sides added together, but cannot be more than either of the sides alone.

1.

16² + b² = 17²

256 + b² = 289

256 - 256 + b² = 289 - 256

b² = 33

√b² = √33

b = 5.74 or 5.7

2.

16² + b² = 20²

256 + b² = 400

256 - 256 + b² = 400 - 256

b² = 144

√b² = √144

b = 12

3.

7² + 9² = c²

49 + 81 = c²

130 = c²

√130 = √c²

11.40 or 11.4 = c

4.

7² + b² = 9²

49 + b² = 81

49 - 49 + b² = 81 - 49

b² = 32

√b² = √32

b = 5.65 or 5.7

5.

a² + 5² = 17²

a² + 25 = 289

a² + 25 - 25 = 289 - 25

a² = 264

√a² = √264

a = 16.24 or 16.2

6.

10² + b² = 15²

100 + b² = 225

100 - 100 + b² = 225 - 100

b² = 125

√b² = √125

b = 11.18 or 11.2

7.

15² + 8² = 16²

225 + 64 = 256

289 ≠ 256

8.

5² + 12² = 13²

25 + 144 = 169

169 = 169

8 0

3 years ago

X squared+ y squared = 2 y = 2x squared – 3 Which of the following describes the system?

cluponka [151]

Answer:

$x=-1,1,-\sqrt{\frac{7}{4} },\sqrt{\frac{7}{4}}$ and $y=-1,\frac{1}{2}$

The ordered pair solutions are $(-\sqrt{\frac{7}{4}},0.5)$ , $(\sqrt{\frac{7}{4}},0.5)$ , $(-1,-1)$ , and $(1,-1)$ .

Step-by-step explanation:

I'm assuming the system is $\left \{ {x^2+y^2=2} \atop {y=2x^2-3}} \right.$ :

$x^2+y^2=2$

$x^2+(2x^2-3)^2=2$

$x^2+(4x^4-12x^2+9)=2$

$x^2+4x^4-12x^2+9=2$

$4x^4-11x^2+9=2$

$4x^4-11x^2+7=0$

$x^4-11x^2+28=0$

$(x^2-7)(x^2-4)=0$

$(4x^2-7)(x^2-1)=0$

$4x^2-7=0$

$4x^2=7$

$x^2=\frac{7}{4}$

$x=\pm\sqrt{\frac{7}{4}}$

$x^2-1=0$

$x^2=1$

$x=\pm1$

$y=2x^2-3$

$y=2(\pm\sqrt{\frac{7}{4}})^2-3$

$y=2({\frac{7}{4}})-3$

$y=\frac{7}{2}-3$

$y=\frac{1}{2}$

$y=2x^2-3$

$y=2(\pm1)^2-3$

$y=2(1)-3$

$y=2-3$

$y=-1$

Therefore, $x=-1,1,-\sqrt{\frac{7}{4} },\sqrt{\frac{7}{4}}$ and $y=-1,\frac{1}{2}$

The ordered pair solutions are $(-\sqrt{\frac{7}{4}},0.5)$ , $(\sqrt{\frac{7}{4}},0.5)$ , $(-1,-1)$ , and $(1,-1)$ .

4 0

2 years ago

Two adjacent supplementary angles are

denis-greek [22]

Answer:

∠BPZ and ∠APZ

Step-by-step explanation:

These two angles share a common side and their non common side lies on a straight line.

8 0

3 years ago

Find the un know value <br> diameter= 9.8<br> circumfrence=?<br> radius=?<br> it is question of pie

Monica [59]

The radius is 4.9 and the Circumference is 9.8π

Step-by-step explanation:

<u>Data:</u>

Diameter = 9.8

Circumference = ?

Radius = ?

<u>Radius</u>

Radius is half of the diameter so radius = $\frac{diameter}{2}$

Radius = $\frac{9.8}{2}$

Radius = 4.9

<u>Circumference</u>

Circumference = 2πr

Circumference = 2π(4.9)

Circumference = 9.8π

Therefore, the radius is 4.9 and the Circumference is 9.8π

Keywords: Circumference

Learn more about circumference at

#LearnwithBrainly

8 0

3 years ago