Answer:
The width is 50 yards and the length is 141 yards.
Step-by-step explanation:
Let's call: L the length of the field and W the width of the field.
From the sentence, the perimeter of the rectangular playing field is 382 yards we can formulate the following equation:
2L + 2W = 382
Because the perimeter of a rectangle is the sum of two times the length with two times the width.
Then, from the sentence, the length of the field is 9 yards less than triple the width, we can formulate the following equation:
L = 3W - 9
So, replacing this last equation on the first one and solving for W, we get:
2L + 2W = 382
2(3W - 9) + 2W = 382
6W -18 +2W = 382
8W - 18 = 382
8W = 382 + 18
8W = 400
W = 400/8
W = 50
Replacing W by 50 on the following equation, we get:
L = 3W - 9
L = 3(50) - 9
L = 141
So, the width of the rectangular field is 50 yards and the length is 141 yards.
Answer:
A
Step-by-step explanation:
Taking the square root of both sides.
PEMDAS order refers to parentheses, exponents, multiplication, division, addition, and subtraction. So, 2*5=10 and 34+10=44.
Answer:
m∠A = 31
b = 13.3
Step-by-step explanation:
Answer:
<u>C</u> -1/2
Step-by-step explanation:
midpoint = sum of end points divide by 2.
here, midpoint = (-3+2)/2
=(-1/2)
