Answer:
This is achieved for the specific case when high quantum number with low resolution is present.
Step-by-step explanation:
In Quantum Mechanics, the probability density defines the region in which the likelihood of finding the particle is most.
Now for the particle in the box, the probability density is also dependent on resolution as well so for large quantum number with small resolution, the oscillations will be densely packed and thus indicating in the formation of a constant probability density throughout similar to that of classical approach.
Answer:
$149.09
Step-by-step explanation:
56.75-14.10=42.65
42.65+41.50=84.15
84.15-11.03=73.12
73.12-7.25=65.87
65.87+83.22=149.09
I'm assuming you meant 1.5 × 10⁴. Remember, when we write in standard form, you need to use ^ to denote it's 'to the power of'. So it would be 1.5 × 10^4.
I'm also assuming you meant in decimal form, because that's already in standard form.
However, the answer is 15,000. This is because you lose one zero when multiplying a decimal with one number after it. For each number after the decimal, you take off a zero. Therefore, the end number is 15,000.
Use the Product Rule: x^ax^b = x^a + b
6x^3 + 1y^2 + 6
Simplify 3 + 1 to 4
6x^4y^2 + 6
Simplify 2 + 6 to 8
<u>= C) 6x^4 y^8</u>
There can only be two outcomes that result from the coon being flipped because there’s only two sides.
