Answer:Suppose the cost stock is x and the cost of fund is y.
Total cost of Nora's portfolio:
100x+200y=3800.....i
Total cost of Erin's portfolio
300x+50y=5350...ii
solving the simultaneous equation by elimination method we proceed as follows:
multiplying eqn by 3 and subtracting ii we get:
550y=6050
thus
y=6050/550
y=11
next, multiply ii by 4 and subtracting i we get:
1100x=17600
x=16
thus the cost of Technology stock was $16 and the cost of mutual fund was $11
Step-by-step explanation:
Answer:
Step-by-step explanation:
-1 1 3 5 7 9 11
That's the answer. If you need a method or a formula, that's a little harder.
L = a + (n - 1)*d
a = -1
L = 11
n = 7
or n is the hard part. If you have 5 means, then you have 6 spaces. So n must be 7 in all
11 = -1 + (7 - 1)*d add 1 to both sides. Combine the brackets
11+1 = -1+1+ 6*d
12 = 6d divide by 6
12/6 = d
2 = d
What this tells you is that each term has 2 added to it to get to the next one.
10 coins in nickels & dimes = $0.70
1 nickel = $0.05
1 dime = $0.10
4 dimes = $0.40
6 nickels = $0.30
4 dimes + 6 nickels = 10 coins
$0.40 + $0.30 = $0.70
The answer is: He has a total of 4 dimes in his pocket.
Answer:
3
5
÷
j
=
3
8
Multiply the numerator of the first fraction by the denominator of the second fraction. Set this equal to the product of the denominator of the first fraction and the numerator of the second fraction.
(
3
5
)
⋅
8
=
j
⋅
3
Step-by-step explanation:Multiply the numerator of the first fraction by the denominator of the second fraction. Set this equal to the product of the denominator of the first fraction and the numerator of the second fraction.
(
3
5
)
⋅
8
=
j
⋅
3
Attached below is the problem that I worked out. And I checked my answer simply by plugging it in