What is 4 to the 2/3 power

1 answer:

8 0

$\bf a^{\frac{{ n}}{{ m}}} \implies \sqrt[{ m}]{a^{ n}} \qquad \qquad
\sqrt[{ m}]{a^{ n}}\implies a^{\frac{{ n}}{{ m}}}\\\\
-------------------------------\\\\
4^{\frac{2}{3}}\implies \sqrt[3]{4^2}\implies \sqrt[3]{(2^2)^2}\implies \sqrt[3]{2^4}\implies \sqrt[3]{2^{3+1}}\implies \sqrt[3]{2^3\cdot 2}
\\\\\\
2\sqrt[3]{2}$

You might be interested in

Help! I have to get this done by tomorrow morning!!!!!

Oksanka [162]

$\frac{1}{5} +\frac{1}{5}+\frac{1}{5}+\frac{1}{5}=\frac{4}{5}$

6 0

3 years ago

Read 2 more answers

The times of all 15 year olds who run a certain race are approximately normally distributed with a given mean Mu = 18 sec and st

Brrunno [24]

The percentage of runners having times less than 14.4 sec is 0.15%. Then the correct option is A.

<h3>What is normal a distribution?</h3>

It is also called the Gaussian Distribution. It is the most important continuous probability distribution. The curve looks like a bell, so it is also called a bell curve.

The times of all 15-year-olds who run a certain race are approximately normally distributed with a given mean (μ) = 18 sec and standard deviation (σ) = 1.2 sec.

The runners have times less than 14.4 sec.

The z-score is a numerical measurement used in statistics of the value's relationship to the mean of a group of values, measured in terms of standards from the mean.

$\rm z-score = \dfrac{X - \mu}{\sigma }\\\\z-score = \dfrac{14.4- 18}{1.2}\\\\z-score = -3$