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3 years ago

Three investors own a company. One partner owns 1/4of the company, while the second partner owns 2/5 of the company. How

Mathematics

2 answers:

svetoff [14.1K]3 years ago

7 0

Answer:

The third partner owns 7/20

Step-by-step explanation:

This is true because 1/4 is 5/20 ans 2/5 is 8/20. Combined that will equal 13/20. 20-13 is 7

Therefore, the answer is 7/20.

oee [108]3 years ago

4 0

Answer:

7/20

Step-by-step explanation:

Use a common denominator (in this case it is 20)

Multiply 1/4 by 5 to get 5/20

Multiply 2/5 by 4 ro get 8/20

5/20 + 8/20 = 13/20 (Combined shares of the 1st and 2nd partner)

subtract 13/20 from 20/20 ro find the remaining share of the company

the last partner owns <u>7/20</u> of the company

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Answer:

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Step-by-step explanation:

If it fell 3 deg every hour for 5 hours so the equation is 3*5 plus a - sign because it dropped degrees

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2 years ago

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KATRIN_1 [288]

Answer:

Step-by-step explanation:

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2 years ago

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3 years ago

Find the mean, variance &a standard deviation of the binomial distribution with the given values of n and p.

MrMuchimi

A random variable following a binomial distribution over $n$ trials with success probability $p$ has PMF

$f_X(x)=\dbinom nxp^x(1-p)^{n-x}$

Because it's a proper probability distribution, you know that the sum of all the probabilities over the distribution's support must be 1, i.e.

$\displaystyle\sum_xf_X(x)=\sum_{x=0}^n\binom nxp^x(1-p)^{n-x}=1$

The mean is given by the expected value of the distribution,

$\mathbb E(X)=\displaystyle\sum_xf_X(x)=\sum_{x=0}^nx\binom nxp^x(1-p)^{n-x}$
$\mathbb E(X)=\displaystyle\sum_{x=1}^nx\frac{n!}{x!(n-x)!}p^x(1-p)^{n-x}$
$\mathbb E(X)=\displaystyle\sum_{x=1}^n\frac{n!}{(x-1)!(n-x)!}p^x(1-p)^{n-x}$
$\mathbb E(X)=\displaystyle np\sum_{x=1}^n\frac{(n-1)!}{(x-1)!((n-1)-(x-1))!}p^{x-1}(1-p)^{(n-1)-(x-1)}$
$\mathbb E(X)=\displaystyle np\sum_{x=0}^n\frac{(n-1)!}{x!((n-1)-x)!}p^x(1-p)^{(n-1)-x}$
$\mathbb E(X)=\displaystyle np\sum_{x=0}^n\binom{n-1}xp^x(1-p)^{(n-1)-x}$
$\mathbb E(X)=\displaystyle np\sum_{x=0}^{n-1}\binom{n-1}xp^x(1-p)^{(n-1)-x}$

The remaining sum has a summand which is the PMF of yet another binomial distribution with $n-1$ trials and the same success probability, so the sum is 1 and you're left with

$\mathbb E(x)=np=126\times0.27=34.02$

You can similarly derive the variance by computing $\mathbb V(X)=\mathbb E(X^2)-\mathbb E(X)^2$ , but I'll leave that as an exercise for you. You would find that $\mathbb V(X)=np(1-p)$ , so the variance here would be

$\mathbb V(X)=125\times0.27\times0.73=24.8346$

The standard deviation is just the square root of the variance, which is

$\sqrt{\mathbb V(X)}=\sqrt{24.3846}\approx4.9834$

7 0

3 years ago

the length of a rectangle is equal to triple the width . if the perimeter is 8 centimeters .what is the length and the width of

madam [21]

Answer:

Length = 3 cm

Width = 1 cm

Step-by-step explanation:

Let the length of rectangle be l and width of rectangle be w.

According to problem,

l = 3w {Length of rectangle is equal to triple the width}

And Perimeter,P = 8 cm

Since, P = 2 ( l + w )

or 8 = 2( l + w)

Plug l =3w in the above perimeter equation.

We get:

8 = 2( 3w + w)

8 = 2(4w)

8 = 8w

or w = 1 cm

Then length ,l = 3w =3 * 1 = 3 cm

Hence length of rectangle is 3cm and width of rectangle is 1cm.

3 0

2 years ago