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Roman55 [17]
3 years ago
14

PLSSSSSS HELPPPPPPP FAST WILL GIVE BRAINLIEST IF CORRECT!! ITS IREADY PLLSSSS HELPP!!

Mathematics
2 answers:
USPshnik [31]3 years ago
7 0

Answer:

3m^4

second one

this ^ means exponent

Step-by-step explanation:

Anarel [89]3 years ago
4 0

Answer:

Number 2

Step-by-step explanation:

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Review the diagram below.
morpeh [17]

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Step-by-step explanation:

you can said bca and its gonna give you that

7 0
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Read 2 more answers
Please help with this question, thank you :)
vovikov84 [41]

Answer:

1/2

((-2)^2-(4*2)^1/3)/abs(-2*2)

-2^2 = 4

4*2 = 8

-2*2 = -4 and abs of that is 4

4-(8)^1/3/4

8^1/3 = 2

4-2 = 2

2/4 = 1/2

Step-by-step explanation:

4 0
3 years ago
Express the quotient of z1 and z2 in standard form given that <img src="https://tex.z-dn.net/?f=z_%7B1%7D%20%3D%20-3%5Bcos%28%5C
Lesechka [4]

Answer:

Solution : -\frac{3}{4}-\frac{3}{4}i

Step-by-step explanation:

-3\left[\cos \left(\frac{-\pi }{4}\right)+i\sin \left(\frac{-\pi \:}{4}\right)\right]\:\div \:2\sqrt{2}\left[\cos \left(\frac{-\pi \:\:}{2}\right)+i\sin \left(\frac{-\pi \:\:\:}{2}\right)\right]

Let's apply trivial identities here. We know that cos(-π / 4) = √2 / 2, sin(-π / 4) = - √2 / 2, cos(-π / 2) = 0, sin(-π / 2) = - 1. Let's substitute those values,

\frac{-3\left(\frac{\sqrt{2}}{2}-\frac{\sqrt{2}}{2}i\right)}{2\sqrt{2}\left(0-1\right)i}

=-3\left(\frac{\sqrt{2}}{2}-\frac{\sqrt{2}}{2}i\right) ÷ 2\sqrt{2}\left(0-1\right)i

= 3\left(-\frac{\sqrt{2}i}{2}+\frac{\sqrt{2}}{2}\right) ÷ -2\sqrt{2}i

= \frac{3\left(1-i\right)}{\sqrt{2}}÷ 2\sqrt{2}i = -3-3i ÷ 4 = -\frac{3}{4}-\frac{3}{4}i

As you can see your solution is the last option.

3 0
3 years ago
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