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3 years ago

Find the value of x in the figure below if the volume is 432 ft3.

Mathematics

2 answers:

Airida [17]3 years ago

8 0

Answer:

The value of x is 18 ft

Step-by-step explanation:

The dimension of the box,

Length, l = x ft

Breadth, b = 4 ft

Height, h = 6 ft

The shape of box is cuboid. The volume of cuboid is lbh

Volume of cuboid (Box) = length × breadth × height

Volume of box = 432 ft³

$lbh=432$

$x\times 4\times 6=432$

$x=\dfrac{432}{24}$

$x=18$

hence, the value of x is 18 ft

dezoksy [38]3 years ago

4 0

Answer:

A. $\displaystyle x = 18$

Step-by-step explanation:

$\displaystyle whl = V → [4][6][x] = 432 \\ \\ \frac{432}{24} = \frac{24x}{24} \\ \\ 18 = x$

I am joyous to assist you anytime.

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Answer:

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Step-by-step explanation:

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3 years ago

How do I go about solving (27x^3/8y^9)^5/3? And what is the role of the numerator and denominator?

MrRissso [65]

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Now, If the exponent was negative like you asked....

$\left( \frac{27x^3}{8y^9}\right)^ {-\frac{5}{3}} \\\\\\ =\left( \frac{8y^9}{27x^3}\right)^ {\frac{5}{3}}\\\\\\ =\left( \frac{(2y^3)^3}{(3x)^3}\right)^ \frac{5}{3} \\\\\\ = \frac{(2y^3)^{3 \times \frac{5}{3} }}{(3x)^{3 \times \frac{5}{3} }} \\\\\\ =\frac{(2y^3)^{5 }}{(3x)^5} \\\\\\ =\frac{32y^{15}}{243x^5}$

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3 years ago

The weight, in pounds, of a newborn baby tt months after birth can be modeled by the function W(t)=1.25t+6.W(t)=1.25t+6. What is

ollegr [7]

Answer:

$6$

Step-by-step explanation:

GIVEN: The weight, in pounds, of a newborn baby $t$ months after birth can be modeled by the function $W(t)=1.25t+6$ .

TO FIND: What is the y-intercept of the function and what is its interpretation in the context of the problem.

SOLUTION:

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if $t=0$

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3 years ago

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faltersainse [42]

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3 years ago

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3 years ago