5.924 g
Step-by-step explanation:
The average weight of a boron atom is 10.811 atomic mass units (AMU). Therefore 3.3 x 10^23 atoms of boron will weight;
3.3 x 10^23 * 10.811 = 3.56763 x 10 ^ 24
One (1) gram = 6.022 x 1023 AMU. Therefore to convert AMU to grams;
3.56763 x 10 ^ 24 / 6.022 x 10^23
= 5.924 g
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Answer:
it is C. An = 2(2)^n
Step-by-step explanation:
Answer:
y=2x+4
if you need more help comment
Answer:
A
Step-by-step explanation:
When you shift down by 5 units, you are basically -5ing to every value in the bottom part of the chart.
For the bottom of the chart, I get:
0,2,8,14
While the top is
1,2,3,4 as nothing changes here.
The only chart like this is A.
The missing side is 17 and rounded it is 20
