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jek_recluse [69]
3 years ago
8

How do you write y=-6/5x-7/5 in standard form

Mathematics
1 answer:
Anvisha [2.4K]3 years ago
8 0
Y=-6/5x-7/5
You add it and move it to the other side
y+6/5x=-7/5
Multiply both sides by 5
5y+6x=-7
Rearrange
6x+5y=-7
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The prime factorization of 441 is
OLga [1]

441 is odd, so we can't divide it by 2.

Since the sum of its digits is 4+4+1=9, which is divisible by 3, we can divide 441 by 3, and we have

441\div 3=147

Which is still divisible by 3, because 1+4+7=12. We have

147\div 3=49

49 is not divisible by 3 anymore, nor by 5 (it doesn't end with 0 or 5).

It is divisible by 7 though, we have

49\div 7=7

and finally,

7\div 7=1

So, the factorization of 441 is

441=3^2\times 7^2

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