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taurus [48]
4 years ago
9

If y varies inversely as x, and y=12 when x=3 find y when x=4

Mathematics
1 answer:
aleksandrvk [35]4 years ago
6 0
First find constant for inversely proportional k(constant)=12×3=36 so in next 36=y4..y=36/4=9
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How can $54,000 be invested part at 8% annual simple Interest and the remainder at 10% annual simple interest so that the intere
Nastasia [14]

Answer:

0.08x = $5400-0.1x Add 0.1x to both sides of the equation.

0.18x = $5400 Divide both sides by 0.18

x = $3000 and $54000-$3000 = $24000

$3,000 is invested at 8%

$2,400 is invested at 10%

Step-by-step explanation:

3 0
4 years ago
Plz help me find zero x on the triangle and show work thanks​
netineya [11]

Answer:

x= 30 degrees

Step-by-step explanation:

This is an isosceles triangle as indicates by the lines on the sides.

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6 0
3 years ago
Consider the following ordered data. 6 9 9 10 11 11 12 13 14 (a) Find the low, Q1, median, Q3, and high. low Q1 median Q3 high (
IrinaVladis [17]

Answer:

Low             Q1                Median              Q3                 High

6                  9                     11                      12.5                14

The interquartile range = 3.5

Step-by-step explanation:

Given that:

Consider the following ordered data. 6 9 9 10 11 11 12 13 14

From the above dataset, the highest value = 14  and the lowest value = 6

The median is the middle number = 11

For Q1, i.e the median  of the lower half

we have the ordered data = 6, 9, 9, 10

here , we have to values as the middle number , n order to determine the median, the mean will be the mean average of the two middle numbers.

i.e

median = \dfrac{9+9}{2}

median = \dfrac{18}{2}

median = 9

Q3, i.e median of the upper half

we have the ordered data = 11 12 13 14

The same use case is applicable here.

Median = \dfrac{12+13}{2}

Median = \dfrac{25}{2}

Median = 12.5

Low             Q1                Median              Q3                 High

6                  9                     11                      12.5                14

The interquartile range = Q3 - Q1

The interquartile range =  12.5 - 9

The interquartile range = 3.5

7 0
3 years ago
A regional planner employed by a public university is studying the demographics of nine counties in the eastern region of an Atl
Brilliant_brown [7]

Answer:

Step-by-step explanation:

Hello!

Given the variables:

X₁: Median Age

X₂: Median Income

b) Considering it from a logical point of view, income changes with age, for example, the more experienced the worker is you would think he would get a better paying job than a younger worker who is just starting. Then the dependent variable will be the median income and the independent variable will be the median age.

a)  and c)

To see if there is a linear regression between the median income and median age you have to conduct a hypothesis test for the slope. If the slope is equal to zero, there is no linear regression between the two variables, if it is different to zero, there is a regression between the two of them:

H₀: β=0

H₁: β≠0

α: 0.05

t= \frac{b-\beta }{Sb} ~~t_{n-2}

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The standard deviation for the slope is Sb= 0.11

t_{H_0}= \frac{0.50-0}{0.11} = 4.545

And the p-value for the test is 0.0022

The p-value is less than the level of significance I choose, so the decision is to reject the null hypothesis. You can conclude that there is a linear regression between these two variables.

The correlation coefficient between the median income and the median age is r= 0.87 ⇒ This means you could expect a positive and strong linear correlation between the two variables.

d)

The slope represents how much the variable Y is modified whenever the variable X increases one unit.

In this example: Is the modification of the population mean of the median income, when the median age increases one year.

5 0
3 years ago
Y-intercept:<br>Rate:<br>Growth or Decay?​
Viefleur [7K]

Answer:

Growth

Step-by-step explanation:

3 0
3 years ago
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