Answer:
x = 55, because if you look the whole entire bar is 180° in total but you dont have to worry about that because that's not what the question is wanting you to look at, If you look really close there is a half and half on both sides so that means there is a 90° angle so you would have to take 90-35 and that is what gives you your missing angle which is 55.
Answer:
Option B. minimum is correct for the first blank
Option C. 6 is correct for second blank.
Step-by-step explanation:
In order to find the maxima or minima of a function, we have to take the first derivative and then put it equal to zero to find the critical values.
Given function is:

Taking first derivative

Now the first derivative has to be put equal to zero to find the critical value

The function has only one critical value which is 5.
Taking 2nd derivative


As the value of 2nd derivative is positive for the critical value 5, this means that the function has a minimum value at x = 5
The value can be found out by putting x=5 in the function

Hence,
<u>The function y = x 2 - 10x + 31 has a minimum value of 6</u>
Hence,
Option B. minimum is correct for the first blank
Option C. 6 is correct for second blank.
Answer:
1/2 X + X -15 + 1/2 X + 100 + X -25 = 540
1/2x + x + 1/2x + x -15 + 100 -25 = 540
3 x + 60 = 540
3x + 60 - 60 = 540 - 60
3/3x = 480/3
x = 160
Step-by-step explanation:
1/2 X + X -15 + 1/2 X + 100 + X -25 = 540
1/2x + x + 1/2x + x -15 + 100 -25 = 540
3 x + 60 = 540
3x + 60 - 60 = 540 - 60
3/3x = 480/3
x = 160
Answer:
Leg side along the wall = x ft = 8 ft
The other leg side = 7+x ft = 7+8=15 ft
The Hypotenuse =9+x ft = 9+8 = 17 ft
Step-by-step explanation:
In the question, the shape of the pool is right triangle.
Let the leg side along the wall to be the x ft
Let the other leg side to be 7+x ft
Let the longest side/hypotenuse to be x+9 ft
Apply the Pythagorean relationship where the sum of squares of the legs equals the square of the hypotenuse
This means;

Expand the terms in brackets

collect like terms

solve for x in the quadratic equation by factorization

Taking the positive value of x;
x=8ft
Finding the lengths
Leg side along the wall = x ft = 8 ft
The other leg side = 7+x ft = 7+8=15 ft
The Hypotenuse =9+x ft = 9+8 = 17 ft
Answer:

Step-by-step explanation:
Given
Regression Equation:

Required
Determine the slope of the regression line
The equation of regression is of the form

Where b represents the slope;
Compare
to the given equation

We have that:




Hence; the slope is:
