Answer:
Al^3+(aq) + PO4^3-(aq) → AlPO4(s)
Explanation:
Step 1: Data given
potassium phosphate = K3PO4
aluminum chloride = AlCl3
potassium chloride = KCl
aluminum phosphate = AlPO4
Step 2: The unbalanced equation
K3PO4(aq) + AlCl3(aq) → KCl (aq)+ AlPO4(s)
On the left side we have 3x K (in K3PO4), on the right side we have 1x K (in KCl). To balance the amount of K on both sides, we have to multiply KCl (on the right side ) by 3. Now the equation is balanced.
K3PO4(aq) + AlCl3(aq) → 3KCl(aq)+ AlPO4(s)
The net ionic equation, for which spectator ions are omitted - remember that spectator ions are those ions located on both sides of the equation - will look like this
Al^3+(aq) + PO4^3-(aq) → AlPO4(s)
Answer:
569K
Explanation:
Q = 3.5kJ = 3500J
mass = 28.2g
∅1 = 20°C = 20 + 273 = 293K
∅2 = x
c = 0.449
Q = mc∆∅
3500 = 28.2×0.449×∆∅
3500 = 12.6618×∆∅
∆∅ = 3500/12.6618
∆∅ = 276.4220
∅2 - ∅1 = 276.4220
∅2 = 276.4220 + ∅1
∅2 = 276.4220 + 293
∅2 = 569.4220K
∅2 = 569K
60% c 8% H and the 300g and molecular formula = 68% and 300g
Answer: 15.3 grams C
Explanation: 1 mole is 6.02x10^23 atoms. We can find the moles of C in 7.675 x 10^23 atoms of C by dividing:
(7.675 x 10^23 atoms C)/(6.02x10^23 atoms C/mole) = 1.275 moles C
The molar mass of carbon is 12g/mole. So the mass of 7.675 x 10^23 atoms is (1.275 moles C)*(12 g/mole C) = 15.3 grams.