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gladu [14]
3 years ago
6

How many moles are there in 32.4 grams of Na

Chemistry
1 answer:
Natalija [7]3 years ago
8 0
Divide that my the molar mass which is 23 so 1.4087 g
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Solution X is a strong base with a pH of 12. Solution X is mixed with solution Y,and the pH of the resulting mixture is 8.Based
myrzilka [38]

The strong Base with a pH of 12 is reduced by 4 units upon being added with solution Y. If you added a strong acid to the strong base, all ions are present in the solution, yes? So every OH- is neutralised by every H+ for example, meaning the resultant pH should be 7. The resultant pH is only 8 however, so solution Y must be a <em>weak acid </em>only!

5 0
3 years ago
What volume (in milliliters) of oxygen gas is required to react with 4.03 g of Mg at STP
Dvinal [7]
Vol.250 before its to much pressure

7 0
3 years ago
Read 2 more answers
Chalk markings cannot be easily rubbed off from a black board if kept for a long time.why?
snow_tiger [21]

The chalk particles embed themselves into the small pores on the surface.

Although a chalkboard seems smooth to the touch, it is quite rough at the microscopic level, with <em>pores</em> that reach below the surface.

When you drag chalk across the board, friction causes small particles of chalk to rub off onto the surface.

If you leave the markings for a long time, some of the chalk particles will work their way into the pores.

A brush will remove the surface particles, but <em>it will not be able to get at the particles in the pores</em>.

3 0
2 years ago
45.7 grams of calcium chloride reacts with an excess of aluminum oxide. How many grams of aluminum chloride will be produced
damaskus [11]
Molar mass (CaCl2) = 40.1 +2*35.5 = 111.1 g/mol
Molar mass (AlCl3) = 27.0 +3*35.5= 133.5 g/ mol

                                               
3CaCl2+Al2O3 -------->3CaO +2AlCl3
mole from reaction              3 mol                                              2 mol
mass from reaction         3mol* 111.1g/mol                             2 mol*133.5g/mol
                                               333.3 g                                            267.0 g
mass from problem              45.7 g                                               x g

Proportion:
  333.3 g  CaCl2  -------   267.0 g AlCl3
  45.7 g   CaCl2   --------   x g    AlCl3

x=45.7*267.0/333.3= 36.6 g AlCl3
5 0
3 years ago
Carbohydrate loading Group of answer choices involves a reduction in the intensity of workouts with a corresponding increase in
SOVA2 [1]

Answer:

the correct option would be:

The group of response options implies a reduction in the intensity of the workouts with a corresponding increase in the percentage of carbohydrate intake for several days before a competition.

Since the carbohydrate load is an increase in glycogen reserves as an energy source accompanied by a decrease in muscle demand. This is often used in high-performance activities, where strict competencies are required.

Although today some professionals do not support that, but rather support a diet with carbohydrates and proteins.

Explanation:

Carbohydrate loading increases glycogen reserves, it is accompanied by a muscle rest plan, without fatigue of muscle fibers.

The purpose of this is to exhaust the muscle fibers in maximum demands such as the competencies, ensuring a necessary energy source that supplies this reaction, for which glycogen reserves are needed.

7 0
3 years ago
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