The answer is 267.93 g
Molar mass of CaBr2 is the sum of atomic masses of Ca and Br:
Mr(CaBr2) = Ar(Ca) + 2Ar(Br)
Ar(Ca) = 40 g/mol
Ar(Br) = 79.9 g/mol
Mr(CaBr2) = 40 + 2 * 79.9 = 199.8 g/mol
The percentage of Br in CaBr2 is:
2Ar(Br) / Mr(CaBr2) * 100 = 2 * 79.9 / 199.8 * 100 = 79.98%
Now make a proportion:
x g in 79.98%
335 g in 100%
x : 79.98% = 335 g : 100%
x = 79.98% * 335 g : 100%
x = 267.93 g
Explanation:
Substances generally tends to specialize as either oxidizing or reducing agents.
An oxidizing agent is an electron acceptor which causes a co-reactant to be oxidized in a reaction.
Examples are:
Non-metals especially oxygen and the halogens.
Other examples are H₂SO₄ , HNO₃, KMnO₄, K₂Cr₂O₇
learn more:
Oxidizing and reducing agents brainly.com/question/5558762''
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