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liubo4ka [24]
3 years ago
14

Describe the process illustrated in the diagram above. How many individuals would exist if the process continued for one more ge

neration?

Chemistry
1 answer:
Dvinal [7]3 years ago
5 0

Answer:

  • <u>The process illustrated can be described as the exponential growth of a population, starting with one individual, with a multiplicative growing rate of 2.</u>

<u></u>

  • <u>If the process continued for one more generation, 8 individuals would exist.</u>

Explanation:

The diagram illustrates the multiplication of individuals (population) by a factor of two. First generation consits of one individual (one green oval), second generation has two individuals (two green ovals), and third generation has four individuals (four green ovals).

Hence, you see that the individuals are growing with a multiplicative rate of 2:

  • First generation: 1 individual

  • Second genertation: 2 individuals = 2 × 1

  • Third generation: 4 individuals = 2 × 2 = 4

Now you can calculate how many individuals would exist if the process continued for one more generation: just multiply the previous generation by 2:

  • Number of individuals in a generation = 2 × number of individuals in the previous generation.

  • Number of individuals in the fourth generation = 2 × number of individuals in the third generation.

  • Number of individuals in the fourth generation = 2 × 4 = 8
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Calculate the percentage of the void space out of the total volume occupied by 1 mole of water molecules. The density of water i
gtnhenbr [62]

Answer:

The percentage of the void space out of the total volume occupied is 93.11%

Explanation:

A mole of water contains 2 atoms of hydrogen and 1 atom of oxygen.

To calculate the volume of a mole of water, we calculate 2 times the volume of the hydrogen atom and 1 times the volume of the oxygen atom

Let's calculate this one after the other.

For the hydrogen, formula for the volume will be

V_{hydrogen = 2 × 4/3 × π × r_{H}^{3}

where r_{H}^{3} = 37 pm which is read as 37 picometer (1 picometer = 10^-12 m) = 37 × 10^{-12} meters

Volume of the hydrogen = 8/3 × (37 × 10^-12)^3 = 4.05 * 10^-31

we multiply this by the avogadro's number = 6.02 * 10^23

= 4.05 * 10^-31 * 6.02 * 10^23 = 2.6 * 10^-8 m^3

We do same for thr oxygen, but this time we do not multiply the volume of the oxygen by 2 as we have only one atom of oxygen

Volume of oxygen = 4/3 * π * (73 * 10^-12) ^3 * avogadro's number = 9.81 * 10^-7 m^3

adding both volumes together, we have 1.24 * 10^-6 m^3 or simply 1.24 ml ( 0.01 m = 1 ml)

Dividing the molar mass of one mole of water by its density, we can get the volume of 1 mole of water

= (18g/mol)/(1 g/ml) = 18 ml/mol

Now we proceed to calculate the volume of void = Total volume - volume of molecule = 18 - 1.24 = 16.76 ml

Now, the percentage of void = volume of void/total volume * 100%

= 16.76/18 * 100% = 93.11%

7 0
3 years ago
What percent of the ocean is euphotic zone
valina [46]
Depth where light intensity falls to one percent<span> of that at the surface, called the euphotic depth</span>
7 0
3 years ago
Please help answering 46)
OLga [1]

Answer:

CO2 is a trigonal planar.

8 0
2 years ago
Read 2 more answers
What do Ta Os and Rh stand for on the periodic table? Transition Metals
IrinaVladis [17]

Answer: Ta is Tantalum, Os is Osmium and Rh is Rhodium

Explanation: All of these elements are in the transition metal group. Ta is part of the early transition metals while Os and Rh belongs to the late transition metals.

5 0
3 years ago
5. What is the final "Celsius" temperature if 2.40 L of gas at 30.5 C is cooled until the volume reaches 1.00 L at constant pres
slega [8]

Answer:

Final temperature of the gas = -146.63 °C

Explanation:

At constant pressure, volume and temperature of the gases are related as:

\frac{V_1}{T_1}=\frac{V_2}{T_2}

Where,

V1 = Initial volume = 1.00 L

V2 = Final volume = 2.40 L

T1 = Initial temperature = 30.5 °C = 30.5 + 273.15 = 303.65 K

Now, substitute the values in the above equation,

\frac{V_1}{T_1}=\frac{V_2}{T_2}

\frac{2.40\;L}{303.65}=\frac{1.00\;L}{T_2}

T_2=\frac{1.00\times 303.65}{2.40}

T2 = 126.52 K

The conversion of T( °C) to T(K) is shown below:

T(K) = T( °C) + 273.15  

T( °C) = T(K) - 273.15

          = 126.52 - 273.15 = -146.63 °C

7 0
3 years ago
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