We know that the sum of all angle measures in a trapezoid is 360* (* means degrees)
Therefore we can construct the equation
(X+28)+(x)+(4x-14)+(4x-14)= 360
Now add like terms
10x = 360
And divide by the coefficient of X (aka 10)
X= 36
Answer:
<em>Equation of line; y = - 6x</em>
Step-by-step explanation:
As we can see from this graph, point ( 0, 0 ) lying on this graph intersects the y - axis such that it forms a y - intercept of 0;
At the same time we can note that the change in y / change in x, in other words the slope, differs by a rise of 6 / run of - 1, 6 / - 1 being a slope of - 6;
If this equation is in slope - intercept form ⇒
y = a * x + b, where a ⇒ slope, and b ⇒ y - intercept,
<em>Equation of line; y = - 6x</em>
Answer:
3x(2x - 3)
Step-by-step explanation:
Given
y = 6x² - 9x ← factor out 3x from each term
= 3x(2x - 3)
Let area of triangle AEC = x
Area of triangle BAC = 1/2 * 15 * 12 = 90
Area of triangle DCA = 1/2 * 15 * 6 = 45
90 = p + x and
45 = q + x Subtracting the 2 equations:-
90 - 45 = p - q
Answer p - q = 45
Let s represent the length of any one side of the original square. The longer side of the resulting rectangle is s + 9 and the shorter side s - 2.
The area of this rectangle is (s+9)(s-2) = 60 in^2.
This is a quadratic equation and can be solved using various methods. Let's rewrite this equation in standard form: s^2 + 7s - 18 = 60, or:
s^2 + 7s - 78 = 0. This factors as follows: (s+13)(s-6)=0, so that s = -13 and s= 6. Discard s = -13, since the side length cannot be negative. Then s = 6, and the area of the original square was 36 in^2.
