Solve the equation in the interval from 270° to 810°

Mathematics

2 answers:

KATRIN_1 [288]4 years ago

5 0

Answer:

the answer should be C,E please give brainliest

Step-by-step explanation

never [62]4 years ago

5 0

Answer:

C. 360

E. 720

Step-by-step explanation:

note: 2pi radians = 360 degrees.

Cos(x) = 1 whenever x = 2k pi where k is an integer, thus

This translates to

cos(x) = 1 when x=0, 360, 720, 1080, ... degrees.

Between 270 and 810, the angles that satisfy cos(x) = 1 are

360 and 720.

So choose C and E

You might be interested in

Is 8 a even or odd number

Ghella [55]

Answer:

even

Step-by-step explanation:

duhhhh

7 0

4 years ago

Factorise the expression 3a2-4ab as far as possible

horsena [70]

In this case, you have to find a common multiple of 3a^2 and 4ab. As only one of the numbers is divisible by two, this means that two cannot go outside of the bracket. The only other aspect that is in both sides of the equation is a, therefore, this goes outside the bracket. The best way to approach this is to divide both sides by a, and this will give you what is inside the bracket. 3a^2 divided by a is 3a, therefore, this is the first aspect in the bracket. -4ab divided by a, leaves -4b. Therefore, these go in the bracket.
3a^2- 4ab simplified is a(3a-4b)
Hope this helps

7 0

3 years ago

Use ΔABC shown below to answer the question that follows:

topjm [15]

Answer:

The correct options are a and b.

Step-by-step explanation:

It is given that triangle ABC with segment AD drawn from vertex A and intersecting side BC.

Two triangle are called similar triangle if their corresponding sides are proportional or the corresponding interior angle are same.

To prove ΔABC and ΔDBA are similar, we have to prove that corresponding interior angles of both triangle as same.

If segment AD is an altitude of ΔABC, then angle ADB is a right angle.

$\angle BDA=90^{\circ}$