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ankoles [38]
3 years ago
10

The digits 2 comma 3 comma 4 comma 5 comma and 2, 3, 4, 5, and 6 are randomly arranged to form a​ three-digit number. ​ (Digits

are not​ repeated.) Find the probability that the number is even and greater than 600.
Mathematics
1 answer:
iren2701 [21]3 years ago
5 0
There are total of 5 digits, of which we arrange 3 of them.
Therefore using permutations we can find total possible 3-number combinations.
5P3 = 5*4*3 = 60

To be greater than 600 means first digit must be 6. (1 possibility)
A number is even only if last digit is even, 2 or 4.  (2 possibilities)
The 2nd digit then can only be 3,5, (2 or 4).    (3 possibilities)
The total possible even 3-digit numbers greater than 600 is product of each digit's possibilities.
---> 1*3*2 = 6

Therefore probability is 6/60 = 1/10.
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Find the radius of a sphere with a surface area of 1024π square inches
agasfer [191]

Answer:

<h2>R = 16 in</h2>

Step-by-step explanation:

The formula of a Surface Area of a sphere:

S.A.=4\pi R^2

R - radius

We have

S.A.=1024\pi\ in^2

Substitute:

4\pi R^2=1024\pi               <em>divide both sides by π</em>

4R^2=1024             <em>divide both sides by 4</em>

R^2=256\to R=\sqrt{256}\\\\R=16\ in

4 0
3 years ago
You owe your mom 10$. You pay her back 7$. Write an expression that can be used to represent this situation.
mezya [45]

Answer:

10$-7$=3$

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
Can you write the equation for a circle if the given point does not lie on the circle? Explain .
Pachacha [2.7K]

Answer:

No

Step-by-step explanation:

The equation of a circle with center (a,b) and radius r is given as:

{(x - a)}^{2}  +  {(y - b)}^{2}  =  {r}^{2}

If a given point (x,y) does not lie on this circle, it will not satisfy its equation.

This means the distance from the point to the center is not equal to the radius.

It is either less or greater than the radius.

Hence you cannot write the equation of the circle.

3 0
2 years ago
Mr. Design is covering rectangular pieces of plywood with fabric to create a wall hanging. Each piece has an area of 12 3/4 squa
ExtremeBDS [4]

6 inches 
6 1/14 inches  
Since area is defined as length multiplied by width, this is a simple matter of division. I suspect this problem is more a matter of handling fractions, so to make things easier, convert the fractions to improper fractions in order to do the math, then convert to proper fractions after you've gotten the result. Since the area of each rectangle is 12 3/4, multiply 12 by 4 and then add 3 to get 51/4 as the area. Doing the same for the values 2 1/8 and 2 1/10 gives sizes of 17/8 and 21/10 for the widths respectively. So 
 51/4 / 17/8 = 51/4 * 8/17 = 408/68 = 6/1 = 6 
 51/4 / 21/10 = 51/4 * 10/21 = 510/84 = 85/14 = 6 1/14
3 0
3 years ago
A data set has a maximum of 84, a minimum of 34, a median of 52.5, an upper quartile of 64, and a lower quartile of 44. Which st
Akimi4 [234]

Answer:

A box and whiskers plot has a box whose endpoints are the interquartile range (25th percentile and 75th percentile), has a dividing line at the median, aka the 50th percentile, and whiskers that extend out to the minimum and the maximum of the data.

Let's sort the info for ease of reference:

min 34, lower quartile 44, median 52.5, upper quartile 64, max 84.

OK, let's go through the statements.

A. The box will go from 44 to 64.

The box goes from the lower quartile to the upper quartile, TRUE

B. A line dividing the box will be at 54.

There's no 54 mentioned at all, FALSE

C. The left whisker will go from 34 to 52.5.

The left whisker goes from the minimum to the lower quartile, 34 to 44 here, FALSE.

D. The right whisker will go from 44 to 84.

The right whisker goes from the upper quartile to the max, 64 to 84 here.  FALSE

If this could help, please mark me brainliest! Have an awesome day too!

4 0
2 years ago
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