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BartSMP [9]
3 years ago
7

In the diagram, bisects ABC. Find mABD and mDBC

Mathematics
1 answer:
Pie3 years ago
7 0

Answer:

mABD=24

mDBC=24

Step-by-step explanation:

First, set up x+15 and 4x-12 as equivalent equations

Subtract x from both sides to get 3x-12=15

Add 12 to get 3x=27

x=9

Plug 9 into the original equations representing the measurements of angles

You should get 24 for both because bisected means both are congruent

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PLZ HELP QUICK Factor the GCF: 12a3b + 8a2b2 − 20ab3. (5 points)
antoniya [11.8K]

Answer:

4ab(3a² + 2ab − 5b²)

Step-by-step explanation:

simply factorize

3 0
4 years ago
Read 2 more answers
A youth basketball coach has 12 kids on his team and he selects 5 kids to start each game. To be fair he wants to start a differ
alisha [4.7K]

_{12}C_5=\dfrac{12!}{5!7!}=\dfrac{8\cdot9\cdot10\cdot11\cdot12}{120}=792

792>20, so yeah, he will be able.

8 0
3 years ago
Radioactive Decay
SpyIntel [72]

Answer:

Percentage of (226Ra) after 900 years is 68%

Step-by-step explanation:

Let P(t) be the amount of (226Ra) present at any time t

Half life of (226 Ra) = 1599 years

If P₀ is initial amount of (226 Ra) then after 1599 years

P(1599)=P₀/2

Decay i amount of radioactive substance is related to time t as

\frac{dP}{dt}=kP(t)\\\\\frac{1}{P}\,dP=kdt\\\\Integrating\,\, both\,\,sides\\\\ln|P|=kt+c\\\\P(t)=Ce^{kt}\\\\at \,\, t=0\,\, P(0)=P_{o}\\\\P(0)=Ce^{k0}\\\\P_{o}=C\\\\then\\\\P(t)=P_{o}e^{kt}

To find value of k

at\,\, t=1599\,years\\\\P(1599)=\frac{P_{o}}{2}\\\\then\\\\\frac{P_{o}}{2} =P_{o}e^{k(1599)}\\\\\frac{1}{2} =e^{k(1599)}\\\\ln|\frac{1}{2}|=k(1599)\\\\k=\frac{ln|\frac{1}{2}|}{1599}=-4.3\times 10^{-3}\\\\\implies P(t)=P_{o}e^{-4.3\times 10^{-3}t}\\\\at\,\, t=900 \\\\P(900)=P_{o}e^{-4.3\times 10^{-3}(900)}\\\\P(900)=0.68P_{o}

Percentage of radioactive element is:

Amount after 900 years=\frac{P(900)}{P_{o}}\times 100\\\\=\frac{0.68P_{o}}{P_{o}}\times 100\%\\\\=68\%

3 0
3 years ago
An equation is shown below:
USPshnik [31]
Asking the Math Gods...


x=2

4 0
4 years ago
A recreation center holds a soccer game every Saturday morning for older teens. The group agreed that there should be at least f
Lyrx [107]

Answer:

They can play for 1 hour and 20 minutes from the beginning of the game.

Step-by-step explanation:

Start playing with 17 players.

At 1 hour, there are 14 players left.

At 1:05, there are 11 players left.

At 1:10, there are 8 players left.

At 1:15, there are 5 players left.

At 1:20, there are 2 players left, and play stops.

They can play for 1 hour and 20 minutes from the beginning of the game.

5 0
4 years ago
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