Answer:
Any number less than 1
Step-by-step explanation:
Let x be the number Lin multiplies by 7/8. So, we have:
(7/8)*x < 7/8
We need to find the possible values for x. Lets start by dividing both sides of our inequality by (7/8) in order to get x alone on the left side.
(7/8)*x / (7/8) < (7/8)/(7/8)
Reordering:
(7/8) / (7/8) * x < (7/8)/(7/8)
As any number divided by itself (except from 0) is equal to 1:
x < 1
So, the number that Lin multiplied by 7/8 MUST be less than 1. This is evident, as any positive number multiplied by a number less than 1 will decrease, doesn't matter if its a negative or positive number.
So, such number is less than 1. Any number less than 1 could be Lin's number.
Answer:
y =3 x
Step-by-step explanation:
The standard equation of a line in point slope form is expressed as;
y -y0 = m(x-x0)
m is the slope
(x0, y0) is the point on the line
Given the line 3x - y = 5
Get the slope
- y = -3x + 5
y = 3x - 5
Slope m = 3
Substitute m = 3 and (-1, -5) into the given formula
y - (-5) = 3(x-(-1))
y+5 = 3(x+1)
y + 3 = 3x+3
y = 3x + 3 - 3
y = 3x
Hence the equation in slope intercept form is y =3 x
Answer:
1
Step-by-step explanation:
5% of 20 is 1
Answer:
The value of account after 8 years is $8580
Step-by-step explanation:
Given in question as :
The principal that invested in an account = $6,000
The annual interest rate compounded quarterly = 4.5%
Time period = 8 years
Now from compound Interest method for quarterly .
Amount = Principal 
Or,Amount = $6,000 
Or, Amount = $6,000 (1.430)
∴ Amount = $8580
Hence the value of account after 8 years is $8580 Answer
Answer:
a) 6 mins
b) 70km/h
c) t= 45
Step-by-step explanation:
a) The bus stops from t=10 to t=16 minutes since the distance the busvtravelled remained constant at 15km
Duration
= 16 -10
= 6 minutes
b) Average speed
= total distance ÷ total time
Total time
= 24min
= (24÷60) hr
= 0.4 h
Average speed
= 28 ÷0.4
= 70 km/h
c) Average speed= total distance/ total time
Average speed
= 80km/h
= (80÷60) km/min
= 1⅓ km/min
1⅓= 28 ÷(t -24)
<em>since</em><em> </em><em>duration</em><em> </em><em>for</em><em> </em><em>return</em><em> </em><em>journey</em><em> </em><em>is</em><em> </em><em>from</em><em> </em><em>t</em><em>=</em><em>2</em><em>4</em><em> </em><em>mins</em><em> </em><em>to</em><em> </em><em>t</em><em> </em><em>mins</em><em>.</em>
(t -24)= 28
t - 32= 28
t= 32 +28
t= 60
t= 
t= 45
*Here, I assume that this is a displacement- time graph, so the distance shown is the distance of the bus from the starting point because technically if it is a distance-time graph, the distance would still increase as the bus travels the 'return journey'.
Thus, distance is decreasing after t=24 and reaches zero at time= t mins so that is the return journey. (because when the bus returns back to starting point, displacement/ distance from starting point= 0km)