We know that
The formula for combinations is
C=n!/[(n-r)!*r!]
where
n is the total number of objects you choose from
r is the number that you choose to arrange
in this problem
n=15 students
r=4 students
C=15!/[(15-4)!*4!]-----> C=15!/[11!*4!]---> (15*14*13*12*11!)/(11!*4*3*2*1)
C=(15*14*13*12)/(24)----->C=1365
the answer is
1365
Answer:
First term a₁ = 3/2 and common ratio r = 2
Step-by-step explanation:
We need to find the first term and common ratio while we are given third term = 6 and seventh term = 96
Since common ratio is required so, the sequence is geometric sequence
The formula used is: 
We are given: third term = 6 i,e

Seventh term = 96

Dividing eq(2) and eq(3)

So, Common Ratio r = 2
Finding First term using eq(1)

So, First term a₁ = 3/2 and common ratio r = 2
Answer:
Step-by-step explanation:
I assume you mean to write a polynomial function. I don't know how righting works.
The simplest one I can think of is
y = 3x⁷