Answer:
<h3>21mi/gn</h3>
Step-by-step explanation:
<h3>7mi/1/3gncalculate the product</h3>
7mi/gn/3simplify the complex fraction
<h3><em>So </em><em>the </em><em>answer </em><em>is=</em><em>2</em><em>1</em><em>m</em><em>i</em><em>/</em><em>gn</em></h3>
<h3><em>Hope </em><em>it </em><em>helps</em></h3>
Number 2 is 7 9/8 but its an improper fraction so you'll have to reduce that since im having trouble doing that.
Number 5 is 9 11/12
Hope this helps!
Answer:
<h2>-8</h2>
Step-by-step explanation:
![4-3[6-2(4-3)]\\\\Follow\:the\:PEMDAS\:order\:of\:operations\\\\\mathrm{Calculate\:within\:parentheses}\:\left[6-2\left(4-3\right)\right] : 4\\\\=4-3\times\:4\\\\\mathrm{Multiply\:and\:divide\:\left(left\:to\:right\right)}\:3\times\:4\::\quad 12\\=4-12\\\\\mathrm{Add\:and\:subtract\:\left(left\:to\:right\right)}\:4-12\:\\\\:\quad -8](https://tex.z-dn.net/?f=4-3%5B6-2%284-3%29%5D%5C%5C%5C%5CFollow%5C%3Athe%5C%3APEMDAS%5C%3Aorder%5C%3Aof%5C%3Aoperations%5C%5C%5C%5C%5Cmathrm%7BCalculate%5C%3Awithin%5C%3Aparentheses%7D%5C%3A%5Cleft%5B6-2%5Cleft%284-3%5Cright%29%5Cright%5D%20%3A%204%5C%5C%5C%5C%3D4-3%5Ctimes%5C%3A4%5C%5C%5C%5C%5Cmathrm%7BMultiply%5C%3Aand%5C%3Adivide%5C%3A%5Cleft%28left%5C%3Ato%5C%3Aright%5Cright%29%7D%5C%3A3%5Ctimes%5C%3A4%5C%3A%3A%5Cquad%2012%5C%5C%3D4-12%5C%5C%5C%5C%5Cmathrm%7BAdd%5C%3Aand%5C%3Asubtract%5C%3A%5Cleft%28left%5C%3Ato%5C%3Aright%5Cright%29%7D%5C%3A4-12%5C%3A%5C%5C%5C%5C%3A%5Cquad%20-8)
Given that the population can be modeled by P=22000+125t, to get the number of years after which the population will be 26000, we proceed as follows:
P=26000
substituting this in the model we get:
26000=22000+125t
solving for t we get:
t=4000/125
t=32
therefore t=32 years
This means it will take 32 years for the population to be 32 years. Thus the year in the year 2032
<span>2s+5>= 49
Subtract 5 from both sides
2s>=44
Divide 2 on both sides
Final Answer: s>=22</span>
