Beamforming can improve network service by using device locations to better target service signals.
This is because, beamforming helps to deliver higher signal quality to the target receiver.
<h3>What is beamforming?</h3>
beamforming can be regarded as application of different radiating elements that is transmitting the same signal.
This signal is usually identical in wavelength and phase, and by reinforcing the waves in a specific direction the goal can be acheived.
Learn more about beamforming at:
brainly.com/question/12809344
The term used to describe whereby old and new media are available via the integration of personal computers and high speed satellite based phone or cable links is: media convergence.
<h3>What's a good illustration of media convergence? </h3>
- Smartphones, laptops, and ipads are the finest instances of media convergence since they combine several forms of digital media, including radio, cameras, TVs, music, and more, into a single, straightforward gadget.
- The blending of formerly separate media platforms and technologies through digitization and computer networking is referred to as media convergence. Another name for this is technical convergence.
- Media ownership concentration, sometimes referred to as media consolidation or media convergence, is the process through which a smaller number of people or organisations come to control a larger portion of the mainstream media.
- According to recent study, there is a rising amount of consolidation in the media sectors, which are already highly concentrated and controlled by a very limited number of companies.
To learn more about media convergence, refer to the following link:
brainly.com/question/25784756
#SPJ4
if(Expression to be tested) {
code to execute
} else if(Expression to be tested) {
code to execute
}
you can have as many else ifs as you want. But that's what it looks like.
Answer:
The correct Answer is 0.0571
Explanation:
53% of U.S. households have a PCs.
So, P(Having personal computer) = p = 0.53
Sample size(n) = 250
np(1-p) = 250 * 0.53 * (1 - 0.53) = 62.275 > 10
So, we can just estimate binomial distribution to normal distribution
Mean of proportion(p) = 0.53
Standard error of proportion(SE) = 
= 
= 0.0316
For x = 120, sample proportion(p) = 
= 
= 0.48
So, likelihood that fewer than 120 have a PC
= P(x < 120)
= P( p^ < 0.48 )
= P(z < 
) (z=
)
= P(z < -1.58)
= 0.0571 ( From normal table )
True anything is available online.
