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spin [16.1K]
3 years ago
12

Explain why the atomic radius of aluminium is smaller than that of sodium.

Chemistry
1 answer:
garik1379 [7]3 years ago
6 0
Okay, to explain this you might have to grab a periodic table.

Do you have one? Good. Look at the most left side of the periodic table. The first group is the largest atoms in the periodic table. If you go to the right of the periodic table, the atoms get progressively smaller and smaller.

Why is this? Don't atoms get more electrons, and so become significantly bigger as they move to the right?

Although atoms do get more electrons as they go to the right, they also get more protons too. Protons pull on electrons and make atoms smaller. Because of this, going from left to right in a periodic table makes the atoms smaller and smaller, since more and more protons are added.

In this scenario, Aluminum is more to the right than Sodium, which means that it has more protons. Because of this, the protons in Aluminum pull more strongly on electrons than sodium, thus making aluminum smaller.

(Just a side note, going down in a periodic table makes the atoms bigger, since new shells are added every time)

Good luck! If you need any help, just ask :))
-T.B.

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love history [14]

Answer:

Answer is option B . This is because water is said to be highly permeable to the underground soil and thus nourishes it , whereas capillary action will make the water flow upward sllowly , but the water is going underground so it is permeability. Also soil is porous too , but that's only if the water is in the soil , here the water is caused to go underground by some force , so porosity isnt the right option

Explanation:

3 0
3 years ago
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Baking soda (NaHCO3) can be added to a fruit mix solution to create a carbonated drink. An example is the reaction between bakin
DanielleElmas [232]

Answer:

74.4 ml

Explanation:

          C₆H₈O₇(aq) + 3NaHCO₃(s) => Na₃C₆H₅O₃(aq + 3CO₂(g) + 3H₂O(l)

Given     15g = 15g/84g/mol = 0.1786mole Sodium Bicarbonate

From equation stoichiometry 3moles NaHCO₃ is needed for each mole citric acid or, moles of citric acid needed is 1/3 of moles sodium bicarbonate used.

Therefore, for complete reaction of 0.1786 mole NaHCO₃ one would need 1/3 of 0.1786 mole citric acid or 0.0595 mole H-citrate.

The question is now what volume of 0.8M H-citrate solution would contain 0.0595mole of the H-citrate? This can be determined from the equation defining molarity. That is => Molarity = moles solute / Liters of solution

=> Volume (Liters) = moles citric acid / Molarity of citric acid solution

=> Volume needed in liters = 0.0.0595 mole/0.80M = 0.0744 Liters or 74.4 ml

6 0
3 years ago
Why is it impossible for a solution to become both more basic and more acidic at the same time?
elena55 [62]

An increase in H+ concentration will decrease OH- concentration is the

reason why it's impossible.

<h3>What is an Acidic and Basic compound?</h3>

An acidic compound has the presence of H+ ions in them while basic

compounds have the presence of OH- ions.

In a solution , as the number of Hydrogen ions increases, it leds to a

corresponding decrease in the Hydroxide ions which is the reason why

they can't coexist at the same time.

Read more about Acidic and basic compounds here brainly.com/question/4046668

4 0
2 years ago
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AlladinOne [14]

Answer : False, there will be two lithium and one oxygen atoms in a unit molecular structure of lithium oxide.

Explanation:

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In order to attain stable electronic configuration it will loose an electron and form positively charge cation.

Li^+=1s^22s^0

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Oxygen being second most electronegative atom requires two electrons to attain noble gas configuration stability and form negatively charge ion with 2- charge.:

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When two atom of lithium and oxygen comes together , one electron from each lithium atom get transferred to an oxygen atom which results in formation of lithium oxide.

2Li^++O^{2-}\rightarrow Li_2O

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3 years ago
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Describe use of H₂S an analytical reagent?<br><br>​
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Answer:

The main use for hydrogen sulfide is in the production of sulfuric acid and elemental sulfur. ... H2S is used to prepare the inorganic sulfides you need to make those products. As a reagent and intermediate, hydrogen sulfide is beneficial because it can prepare other types of reduced sulfur compounds.

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