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spin [16.1K]
4 years ago
12

Explain why the atomic radius of aluminium is smaller than that of sodium.

Chemistry
1 answer:
garik1379 [7]4 years ago
6 0
Okay, to explain this you might have to grab a periodic table.

Do you have one? Good. Look at the most left side of the periodic table. The first group is the largest atoms in the periodic table. If you go to the right of the periodic table, the atoms get progressively smaller and smaller.

Why is this? Don't atoms get more electrons, and so become significantly bigger as they move to the right?

Although atoms do get more electrons as they go to the right, they also get more protons too. Protons pull on electrons and make atoms smaller. Because of this, going from left to right in a periodic table makes the atoms smaller and smaller, since more and more protons are added.

In this scenario, Aluminum is more to the right than Sodium, which means that it has more protons. Because of this, the protons in Aluminum pull more strongly on electrons than sodium, thus making aluminum smaller.

(Just a side note, going down in a periodic table makes the atoms bigger, since new shells are added every time)

Good luck! If you need any help, just ask :))
-T.B.

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A passenger elevator travels from the first floor to the 60th floor, a distance of 210 m, in 35s. What is the elevator’s speed?
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Explanation:

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3 years ago
Did diagram shows embryo development of four different animals. How is this evidence used to suggest that life changes over time
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5 0
4 years ago
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What is the percent by weight (w/w%) of sugar in soda? Assume the average mass of sugar in soda is 23.0 g and the total mass is
Nina [5.8K]

The percent by weight (w/w%) of sugar in soda : 6.216%

<h3>Further explanation</h3>

Given

mass of sugar = 23 g

total mass = 370 g

Required

the percent weight

Solution

%weight = (mass of solute : mass of solution) x 100%

solute = sugar

solution = solvent + solute = water + sugar

percent weight of sugar in soda :

= (23 : 370) x 100%

= 6.216 %

7 0
3 years ago
Croquet balls must have a mass of 0.50 kg. A red croquet ball, moving at 10
julsineya [31]

The final speed of the  green ball : 8.5 m/s

<h3>Further explanation</h3>

Given

mass of Croquet ball = 0.5 kg

v₁= 10 m/s

v₁'= 1.5 m/s

Required

the final speed

Solution

The law of conservation of momentum

m₁v₁ + m₂v₂ = m₁v₁ '+ m₂v₂' (1=red croquet ball, 2=green croquet ball)

v₂=0 (at rest)

Input the value :

\tt 0.5\times 10+0.5\times 0=0.5\times 1.5+0.5\times v_2'\\\\5=0.75+0.5v_2\\\\4.25=0.5v_2\rightarrow v_2=8.5~m/s

8 0
3 years ago
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