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3 years ago

Are all acids dangerous? Give at least two examples to show what you mean.

Chemistry

1 answer:

juin [17]3 years ago

4 0

Answer:

Laboratory acids are far too dangerous to taste, but you will have swallowed some dilute weak acids. Acids have a sour taste, like vinegar, which contains ethanoic acid, and lemons, which contain citric acid. These are safe to use in food, but they can still hurt if they get into a cut or into your eyes.

Explanation:

They can safely be consumed and do not irritate the skin. However, at greater concentrations weak acids can be harmful. Acids can react violently with water and are harmful in the presence of moisture in the mouth or eyes or in proximity with other aqueous solutions.

hope that helps!

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2 Upper P Upper O Upper C l Subscript 3 Baseline (g) + heat double-headed arrow 2 Upper P Upper C l Subscript 3 Baseline (g) + U

gregori [183]

Answer:

The equilibrium will shift left.

Explanation:

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2 years ago

Look at the diagram. Which shows the correct arrangement of electrons in a hydrogen molecule?

skelet666 [1.2K]

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3 years ago

A toy car is pushed 10 meters in 5 seconds. What is the speed of the toy car in meters per second?

dedylja [7]

The answer is C because the toy car goes 2 meters per each second which in the end 2x5=10.

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2 years ago

Sample of gas initially occupies 4.25 L at a pressure of 0.850 atm at 23.0°C. What will the volume be if the temperature is chan

Aliun [14]

Answer: 2.34 L

Explanation:

Combined gas law is the combination of Boyle's law, Charles's law and Gay-Lussac's law.

The combined gas equation is,

$\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}$

where,

$P_1$ = initial pressure of gas = 0.850 atm

$P_2$ = final pressure of gas = 1.50 atm

$V_1$ = initial volume of gas = 4.25 L

$V_2$ = final volume of gas = ?

$T_1$ = initial temperature of gas = $23.0^oC=273+23.0=293.0K$

$T_2$ = final temperature of gas = $11.5^oC=273+11.5=284.5K$

Now put all the given values in the above equation, we get:

$\frac{0.850\times 4.25}{293.0K}=\frac{1.50\times V_2}{284.5}$

$V_2=2.34L$

Thus the final volume will be 2.34 L

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3 years ago

N2+3H2=2NH3

polet [3.4K]

Answer:

$\large \boxed{\text{6.7 mol NH}_{3}}$

Explanation:

N₂ + 3H₂⟶ 2NH₃

n/mol: 10

The molar ratio is 2 mol NH₃:3 mol H₂.

$\text{Moles of NH}_{3} = \text{ 10 mol H}_{2} \times \dfrac{\text{2 mol NH}_{3}}{\text{3 mol H}_{2}}= \textbf{6.7 mol NH}_{\mathbf{3}}\\\\\text{The reaction produces $\large \boxed{\textbf{6.7 mol NH}_{\mathbf{3}}}$}$

7 0

3 years ago