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jekas [21]
3 years ago
11

6PbO + O2 → 2Pb304 a. How many grams of Pb304 are produced from 8.50 grams of lead(II) oxide?

Chemistry
1 answer:
AlladinOne [14]3 years ago
7 0

Answer:

8.70g of Pb3O4

Explanation:

6PbO + O2 → 2Pb3O4

Molar Mass of PbO = 207 + 16 = 223g/mol

The mass of the PbO from the balanced equation = 6 x 223 = 1338g

Molar Mass of Pb3O4 = (3x207) +(16x4) = 621 + 64 = 685g/mol

Mass of Pb3O4 from the balanced equation = 2 x 685 = 1370g

From the equation,

1338g oh PbO produced 1370g of Pb3O4.

Therefore, 8.50g of PbO will produce = (8.5 x 1370)/1338 = 8.70g of Pb3O4

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3 years ago
Espresso Coffee House is designing a coffee mug that keeps liquids hot. The research department tested several different materia
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Luda [366]
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3 years ago
By titration, it is found that 28.5 mL of 0.183 M NaOH(aq) is needed to neutralize 25.0 mL of HCl(aq). Calculate the
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*Text me at 561-400-5105 for private tutoring if interested: I can do homework, labs, and other assignments :)

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