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jekas [21]
3 years ago
11

6PbO + O2 → 2Pb304 a. How many grams of Pb304 are produced from 8.50 grams of lead(II) oxide?

Chemistry
1 answer:
AlladinOne [14]3 years ago
7 0

Answer:

8.70g of Pb3O4

Explanation:

6PbO + O2 → 2Pb3O4

Molar Mass of PbO = 207 + 16 = 223g/mol

The mass of the PbO from the balanced equation = 6 x 223 = 1338g

Molar Mass of Pb3O4 = (3x207) +(16x4) = 621 + 64 = 685g/mol

Mass of Pb3O4 from the balanced equation = 2 x 685 = 1370g

From the equation,

1338g oh PbO produced 1370g of Pb3O4.

Therefore, 8.50g of PbO will produce = (8.5 x 1370)/1338 = 8.70g of Pb3O4

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In a first-order decomposition reaction, 50.0% of a compound decomposes in 10.5 min.
mihalych1998 [28]

In this reaction 50% of the compound decompose in 10.5 min thus, it is half life of the reaction and denoted by symbol t_{1/2}.

(a) For first order reaction, rate constant and half life time are related to each other as follows:

k=\frac{0.6932}{t_{1/2}}=\frac{0.6932}{10.5 min}=0.066 min^{-1}

Thus, rate constant of the reaction is 0.066 min^{-1}.

(b) Rate equation for first order reaction is as follows:

k=\frac{2.303}{t_{1/2}}log\frac{[A_{0}]}{[A_{t}]}

now, 75% of the compound is decomposed, if initial concentration [A_{0} ] is 100 then concentration at time t [A_{t} ] will be 100-75=25.

Putting the values,

0.066 min^{-1}=\frac{2.303}{t}log\frac{100}{25}=\frac{2.303}{t}(0.6020)

On rearranging,

t=\frac{2.303\times 0.6020}{0.066 min^{-1}}=21 min

Thus, time required for 75% decomposition is 21 min.

8 0
3 years ago
Calculate the following quantity: molarity of a solution prepared by diluting 45.45 mL of 0.0404 M ammonium sulfate to 550.00 mL
dybincka [34]

Answer:

M_2=3.34x10^{-3}M

Explanation:

Hello!

In this case, since a dilution process implies that the moles of the solute remain the same before and after the addition of diluting water, we can write:

M_1V_1=M_2V_2

Thus, since we know the volume and concentration of the initial sample, we compute the resulting concentration as shown below:

M_2=\frac{M_2V_2}{V_1} =\frac{45.45mL*0.0404M}{550.00mL}\\\\M_2=3.34x10^{-3}M

Best regards!

5 0
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Answer:

H2Br + 2KOH ----- K2Br + 2H2O

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What halogen can react with sodium chloride solution to produce chlorine?
ozzi

Answer:

As electro-negativity decreases from Florine to downwards in the group and only Florine is above Chlorine, so Florine should react with sodium chloride solution to produce chlorine.  

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5 0
2 years ago
If 2 acid have ph value 3 and 5 respectively, which will be more acidic? Why?​
nataly862011 [7]

Answer:

A lower ph is always more acidic, due to the increased concentration of hydrogen ions in the solution/substance.

A ph of 3 is 100 times more acidic than a pH of 5, and this is due to the increments on the scale.

6 0
3 years ago
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