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2 years ago

10

I need help ASAP! How many reactants and products are in each element according to the chemical equation above. Please explain t

oo.

1 answer:

Nikitich [7]2 years ago

6 0

Answer: 1,4,1 for the reactants
3,1,4,1 for the products

Explanation:
The products are equal to the reactants because of the conservation of matter.

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How many moles of ag are formed by the complete reaction of 28.3 mol of pb?

levacccp [35]

<span>Answer: 56.6 moles Explanation: 28.3 moles of Pb would produce twice as much moles as Ag. 28.3 X (2moles Ag/ 1 mol Pb) = 56.6 moles of Ag.</span>

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3 years ago

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3 years ago

How does a chemist count the number of particles in a given number of moles of a substance?

jolli1 [7]

The chemist the count the number of particles (Atoms, Molecules or Formula Unit) in a given number of moles of a substance by using following relationship.

Moles = # of Particles / 6.022 × 10²³

Or,

# of Particles = Moles × 6.022 × 10²³

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2 years ago

Concentrated hydrogen peroxide solutions are explosively decomposed by traces of transition metal ions (such as Mn or Fe): 2H2O2

zalisa [80]

Answer:

23.0733 L

Explanation:

The mass of hydrogen peroxide present in 125 g of 50% of hydrogen peroxide solution:

$Mass=\frac {50}{100}\times 125\ g$

Mass = 62.5 g

Molar mass of $H_2O_2$ = 34 g/mol

The formula for the calculation of moles is shown below:

$moles = \frac{Mass\ taken}{Molar\ mass}$

Thus, moles are:

$moles= \frac{62.5\ g}{34\ g/mol}$

$moles= 1.8382\ mol$

Consider the given reaction as:

$2H_2O_2_{(aq)}\rightarrow2H_2O_{(l)}+O_2_{(g)}$

2 moles of hydrogen peroxide decomposes to give 1 mole of oxygen gas.

Also,

1 mole of hydrogen peroxide decomposes to give 1/2 mole of oxygen gas.

So,

1.8382 moles of hydrogen peroxide decomposes to give $\frac {1}{2}\times 1.8382 mole of oxygen gas. Moles of oxygen gas produced = 0.9191 molGiven: Pressure = 746 torr
The conversion of P(torr) to P(atm) is shown below:
[tex]P(torr)=\frac {1}{760}\times P(atm)$

So,

Pressure = 746 / 760 atm = 0.9816 atm

Temperature = 27 °C

The conversion of T( °C) to T(K) is shown below:

T(K) = T( °C) + 273.15

So,

T₁ = (27 + 273.15) K = 300.15 K

Using ideal gas equation as:

PV=nRT

where,

P is the pressure

V is the volume

n is the number of moles

T is the temperature

R is Gas constant having value = 0.0821 L.atm/K.mol

Applying the equation as:

0.9816 atm × V = 0.9191 mol × 0.0821 L.atm/K.mol × 300.15 K

<u>⇒V = 23.0733 L</u>

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2 years ago

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Answer:

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Explanation:

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1 year ago

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