Answer:
0.16 L
Explanation:
Step 1: Write the balanced equation
C₃H₈(g) + 5 O₂(g) → 3 CO₂(g) + 4 H₂O(g)
Step 2: Calculate the moles of CO₂ produced from 0.012 moles of O₂
The molar ratio of O₂ to CO₂ is 5:3. The moles of CO₂ produced are 3/5 × 0.012 mol = 0.0072 mol.
Step 3: Calculate the volume occupied by 0.0072 moles of CO₂ at standard temperature and pressure
At STP, 1 mole of CO₂ occupies 22.4 L.
0.0072 mol × 22.4 L/1 mol = 0.16 L
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N2 is a diatomic molecule as it is composed of 2 atoms of the same element, covalently bonded to each other in this case Nitrogen.
Answer:
1280J are required.
Explanation:
Heat of fusion is defined as the amount of heat required to change its state from liquid to solid at its melting point at constant pressure.
As heat of fusion of gold is 64J/g, there are required 64J to melt 1g of gold at its melting point. The energy required to melt 20g is:
20g * (64J/g) =
1280J are required
Molar mass (NH₄)₂CO₃ = <span>96.09 g/mol
1 mole ---------> 96.09 g
0.500 moles ----> ?
0.500 * 96.09 = 48.045 g of </span><span>(NH₄)₂CO₃
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In this case a double displacement reaction will take place.
