Answer:
Bond Price= 816.29
Explanation:
Giving the following information:
YTM= 0.075
Coupon= 0.058*1,000= 58
Years to maturity= 23 years
Face value= 1,000
<u>To calculate the price of the bond, we need to use the following formula:</u>
Bond Price= cupon*{[1 - (1+i)^-n] / i} + [face value/(1+i)^n]
Bond Price= 58*{[1 - (1.075^-23)] / 0.075} + [1,000/(1.075^23)]
Bond Price= 626.79 + 189.5
Bond Price= 816.29
Inventory turnover = Cost of goods sold / Average Inventory
Average Inventory = (Beginning Inventory + Ending Inventory) / 2
= ($20,000 + $40,000) / 2
= $30,000
Inventory turnover = $360,000 / $30,000
= 12 times.
Answer:
voluntary contribution $97150
Explanation:
data provided:
tax rate: 2.3%
reserve ratio- 8-10%
average payroll = $971,500
Assume voluntary contribution ="X
"
From the information given in the question we have
%
here we have taken max reserve ratio i.e. 10%
= $97150
we know that, from the question present contribution minus benefit is equal to $93,500
hence, extra contribution = 97150 - 93500 = $3650
extra contribution = $3650
Answer:
a. Three (3).
b. Equity.
c. Liability.
d. Asset.
e. Account.
Explanation:
a. Balance sheet accounts are arranged into three general categories. These are asset, liability and equity.
b. Common Stock and Dividends are examples of equity accounts.
c. Accounts Payable and Note Payable are examples of liability accounts.
d. Accounts Receivable, Prepaid Accounts, Supplies, and Land are examples of asset accounts.
e. An account is a record of increases and decreases in a specific asset, liability, equity, revenue, or expense item.
<span>120
The simple answer is that 5 items can be arranged 5! (5 factorial) different ways. But let's expand upon that brief answer. We have 5 jobs and 5 machines with which to perform those jobs. So let's look at the 1st machine. Any of 5 of the jobs may be assigned to it. Now we have 4 jobs left unassigned. So let's look at the 2nd machine. For that machine, any of the 4 remaining jobs may be assigned to it, leaving 3 unassigned jobs. We can continue in that fashion, assigning at random one the of 3 remaining jobs to the 3rd machine, one of the 2 remaining jobs to the 4th machine, and finally, the only unassigned job to the 5th machine. So there's 5 * 4 * 3 * 2 * 1 = 5! = 120 different ways to assign those 5 jobs to all 5 machines.</span>
