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kherson [118]
3 years ago
11

Mt. McKinley, in Alaska, is the highest mountain in North America at 20,320

Mathematics
1 answer:
gladu [14]3 years ago
6 0

Answer:

12700 feet

Step-by-step explanation:

Do 5/8 of 20,320

Do 20320 divided by 8 which is 2540

Do 2540 times 5 which is 12700

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Use the graph to find the bear’s average heart rate when it’s active and when it hibernating
lorasvet [3.4K]

we know that

the rate of a linear equation  is equal to the slope

Step 1

Find the  bear’s average heart rate when it’s active

Let

A(1.5,90)   B ( 2,120)

the slope is equal to

m=(y2-y1)/(x2-x1)

m=(120-90)/(2-1.5)=30/0.5

m=60 heartbeats/min

therefore

the answer part a) is

the bear’s average heart rate when it’s active is 60 heartbeats/min

Step 2

Find the  bear’s average heart rate when it’s hibernating

Let

A(1.5,18)   B ( 2,24)

the slope is equal to

m=(y2-y1)/(x2-x1)

m=(24-18)/(2-1.5)=6/0.5

m=12 heartbeats/min

therefore

the answer part b) is

the bear’s average heart rate when it’s hibernating is 12 heartbeats/min


7 0
3 years ago
22 is to 555 as 55 is to
GalinKa [24]

Answer:

If I'm not mistaken I believe it is 100

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
Please help marking brainliest
REY [17]

Answer:

42.5 if rounding 43 for B

Step-by-step explanation:

P is the variable so put 100 under it

Then on the first empty fraction put 17/40

Cross multiply

You will get 40p=17x100

So then you multiply 17 by 100

1700

divided both sides by 40

Get the variable alone

Divide 1700 by 40

get 42.5

If your teacher is as annoying as mine round to 43

4 0
3 years ago
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Max has x dollars. Keisha has four more dollars than Max.
Dimas [21]
Max has X, and as Keisha has four more,
Keisha is 4+x

The total amount is x+x+4
2x+4
8 0
4 years ago
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Determine the equation of the line that passes through the points of intersection of the graphs of the quadratic functions f(x)
timofeeve [1]

Answer:x-2y-2=0

Step-by-step explanation:

Given :

f(x) = x^2 - 4 \\ g(x) = - 3x^2 + 2x + 8

Point of intersection :

f(x)=g(x)\\x^2-4=-3x^2+2x+8\\4x^2-2x-12=0\\2x^2-x-6=0\\2x^2-4x+3x-6=0\\2x(x-2)+3(x-2)=0\\(x-2)(2x+3)=0\\x=2\,,\,\frac{-3}{2}

x=2\,;f(2)=2^2-4=0\\x=\frac{-3}{2}\,; f\left ( \frac{3}{2} \right )=\left ( \frac{3}{2} \right )^2-4=\frac{-7}{4}=-1.75

So, we have points \left ( 2,0 \right )\,,\,\left ( -1.5,-1.75\ \right )

Equation of line passing through two points \left ( x_1,y_1 \right )\,,\,\left ( x_2,y_2 \right ) is given by y-y_1=\frac{y_2-y_1}{x_2-x_1}\left ( x-x_1 \right )

Let \left ( x_1,y_1 \right )=\left ( 2,0 \right )\,,\,\left ( x_2,y_2 \right )=\left ( -1.5,-1.75\ \right )

So, equation is as follows :

y-0=\frac{-1.75-0}{-1.5-2}\left ( x-2 \right )\\y=\frac{-1.75}{-3.5}\left ( x-2 \right )\\y=\frac{1}{2}(x-2)\\2y=x-2\\x-2y-2=0

4 0
4 years ago
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