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grandymaker [24]
2 years ago
5

i currently have alot of points im only giving out a little but i will give thanks, brainliest, and 5 star

Mathematics
2 answers:
devlian [24]2 years ago
5 0

Answer:

ilyilyilyilyily thank you

Aloiza [94]2 years ago
5 0

Answer:

thats so sweet thank you!!!

Step-by-step explanation:

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I need help assap
Bad White [126]
It’s 2=x because you have start with 2 then 5
5 0
2 years ago
1) You are designing a new kiddie soccer arena. The area of the rectangular
nikdorinn [45]

Answer:

The length of the rectangular field is 12 ft and the width is 5 ft.

Step-by-step explanation:

The area of a rectangle is:

\text{Area} = \text{length}\times \text{width}

The area of a rectangular field is, <em>A</em> = 60 ft.

The length of the field is:

l = w + 7

Compute the width of the field as follows:

\text{Area} = \text{length}\times \text{width}

60=(w+7)\times w\\\\60=w^{2}+7w\\\\w^{2}+7w-60=0\\

Factorize the last equation by splitting the middle term as follows:

w^{2}+7w-60=0\\w^{2}+12w-5w-60=0\\w(w+12)-5(w+12)=0\\(w-5)(w+12)=0

Now, since the width of rectangular field cannot be negative, the width is 5 ft.

Compute the length as follows:

l = w + 7

 = 5 + 7

 = 12

The length of the rectangular field is 12 ft.

7 0
3 years ago
No idea what to do here help is appreciated :)
const2013 [10]

Answer:

Where ??

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
Spencer Ward purchased a new riding mower for $1,989. He made a 15% down payment and financed the remainder. What amount did he
Ostrovityanka [42]
The amount of the down payment is
1,989×0.15=298.35

Amount financed is
1,989−298.35=1,690.65
4 0
3 years ago
Rectangular swimming pool has an area of (70x + 10) square feet. Find possible dimensions of the pool.
andrew11 [14]

a rectangle's area is simply width * length, so is the product of two factors.

in this case, we know that product, is 70x + 10, so, how can we tease out the factors from it?

well, our GCF from 70x and 10 is "10", but 10 itself is factorable into "2" and "5", so we can simply use that GCF and troupe to see what it might be.

\bf \stackrel{\textit{common factor of 10}}{\stackrel{width}{10}\stackrel{length}{(7x+1)}}~\hfill \stackrel{\textit{common factor of 2}}{\stackrel{width}{2}\stackrel{length}{(35x+5)}}~\hfill \stackrel{\textit{common factor of 5}}{\stackrel{width}{5}\stackrel{length}{(14x+2)}}

7 0
3 years ago
Read 2 more answers
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