Answer:
The diluted solution is 0.65 M
Explanation:
Dilution formula to solve the problem is:
M concentrated . V concentrated = M Diluted . V diluted
We can also make a rule of three though.
In 1000 mL of concentrated solution, we have 13.1 moles of HNO₃
So in 25 mL we have (25 . 13.1 ) / 1000 = 0.327 moles of HNO₃
This moles are also in 0.500 L of diluted solution, the new molarity will be:
0.327 mol / 0.5L = 0.65 M
Molarity of diluted solution must be always lower than concentrated solution, otherwise the excersise is wrong.
If we replace in the formula
13.1 M . 25 mL = 500 mL . M diluted
M diluted = 13.1 m . 25 mL / 500 mL = 0.65 M
Sodium Carbonate(NaCO3) gives off heat hence the reactions involving Na2CO3 are exothermic.
Hope this helps!
Do what i don’t see nothing
The relationship between substrate concentration and the rate of reaction of a reaction involving an enzyme as catalyst is not linear. At the start, the initial rate is high since there is high enzyme activity but as the reaction proceeds the rate of reaction gradually decreases as the substrate has all been used up.
The name for NH3 is Nitrogen trihydride.