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marta [7]
3 years ago
5

An atom has 8 protons, 8 neutrons and 9 electrons. is thus a cation, anion, or neutral atom?​

Chemistry
1 answer:
Black_prince [1.1K]3 years ago
7 0

Answer:

It is an <u>Anion</u> because there are more electrons than protons making it negative

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2 years ago
What is empirical and moleculer formula?.
den301095 [7]
The molecular formula shows the exact number of molecules. Therefor, the empirical formula is the simplest formula of the molecular formula
4 0
3 years ago
Write a hypothesis:<br> What is the mole ratio of the cation and the anion in a precipitate?
tankabanditka [31]

Answer:

The mole ratio of the cation and the anion in a precipitate is a simple fraction. ( im sorry if this dosent help a lot.)

Explanation:

8 0
3 years ago
Michelle is trying to find the average atomic mass of a sample of an unknown
GREYUIT [131]

The average atomic mass of her sample is 114.54 amu

Let the 1st isotope be A

Let the 2nd isotope be B

From the question given above, the following data were obtained:

  • Abundance of isotope A (A%) = 59.34%
  • Mass of isotope A = 113.6459 amu
  • Mass of isotope B = 115.8488 amu
  • Abundance of isotope B (B%) = 100 – 59.34 = 40.66%
  • Average atomic mass =?

The average atomic mass of the sample can be obtained as follow:

Average \: atomic \: mass \:  =  \frac{mass \: of \: A \times A\%}{100}  + \frac{mass \: of \: B \times B\%}{100}  \\  \\ Average \: atomic \: mass \:  =  \frac{113.6459\times 59.34}{100} + \frac{115.8488\times 40.66}{100} \\  \\ Average \: atomic \: mass \:  = 114.54 \: amu  \\  \\

Thus, the average atomic mass of the sample is 114.54 amu

Learn more about isotope: brainly.com/question/25868336

3 0
2 years ago
A photon has 8.0 × 10–15 J of energy. Planck’s constant is 6.63 × 10–34 J•s. What is the frequency of the photon
german
The formula is:
frequency * h (Planck's constant) = Energy
So, to find frequency you need just divide energy by the constant:
frequency = (8 * 10^-15 J) / (6.63 * 10^-34 J*s) = 1.2 * 10^19 1/s or 1.2 * 10^19 Hz
5 0
3 years ago
Read 2 more answers
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