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marta [7]
3 years ago
5

An atom has 8 protons, 8 neutrons and 9 electrons. is thus a cation, anion, or neutral atom?​

Chemistry
1 answer:
Black_prince [1.1K]3 years ago
7 0

Answer:

It is an <u>Anion</u> because there are more electrons than protons making it negative

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A ______ is a process in which the physical and chemical properties of the original substances change as new substances are form
Jlenok [28]

Answer:

chemical change

Explanation:

In chemical change , considerable amount of heat is used , hence a change in substance formed

7 0
3 years ago
Read 2 more answers
The mass of h2 produced by reaction of 1.80 g al and 6.00 g h2so4 is 0.112 g. what is the percent yield?
nydimaria [60]
First, let us write the reaction. We know that the reactants are Aluminum and Sulfuric acid, and one of the products is hydrogen. That means the reaction is a single replacement reaction as shown below:

2 Al + 3 H₂SO₄ = 3 H₂ + Al₂(SO₄)₃

Next, let us determine which of the reactants is limiting:

1.80 g Al (1 mol/26.98 g)(3 mol H₂SO₄/2 mol Al)(98 g H₂SO₄/mol) = 9.807 g

It would need 9.807 g. But the only available amount is 6 g. That means that H₂SO₄ is the limiting reactant. We use 6 g as the basis to know the theoretical yield:

6 g*(1 mol H₂SO₄/98 g)*(3 mol H₂/ 3 mol H₂SO₄)*(2 g /mol H₂) = 0.122 g

Therefore, the percent yield is equal to
Percent yield = (0.112 g/0.122 g)*100
Percent yield = 91.8%
3 0
3 years ago
Which states that the volume of a gas is proportional to the moles of the gas when pressure and temperature are
AveGali [126]
Avocados can be a healthy source of nutrients
8 0
3 years ago
Complete and balance the following reactions ?<br> uo^2+ +cr2o^2-7 ــــــــــــــــ uo2+ +cr3+
motikmotik
I think the answer is Fe. Hope it help!
7 0
3 years ago
Combustion analysis of a 13.42-g sample of the unknown organic compound (which contains only carbon, hydrogen, and oxygen) produ
pentagon [3]

Answer: molecular formula = C12H16O8

Explanation:

NB Mm CO2= 44g/mol

Mm H2O= 18g/mol

Moles of CO2 = 36.86/44=0.84mol

0.84mole of CO2 has 0.84 mol of C

Moles of H2O = 10.06/18= 0.56mol

1mol of H20 contains 1mol of O and 2 mol H,

Hence there are 0.56mol O and (0.56×2)mol H

Hence the compound contains

C= 0.84 mol H= 1.12mol O=0.56mol

Divide through by smallest number

C= 0.83/0.56= 1.5mol

H= 1.12/0.55= 2mol

O= 0.56/0.56= 1mol

Multiply all by 2 to have whole number of moles = 3:4:2

Hence empirical formula= C3H4O2

(C3H4O2)n = 288.38

[(12×3) + 4+(16×2)]n= 288.38

72n=288.38

n= 4

:. Molecular formula=(C3H4O2)4= C12H16O8

7 0
3 years ago
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