<span>The orange and yellow spheres represents Protons and neutrons in this model of an atomic nucleus.Protons and neutrons are heavier than electrons and reside in the nucleus at the center of the atom. Electrons are extremely lightweight and exist in a cloud orbiting the nucleus.</span>
The first one is Solid, or A.
The second: B or liquids.
Third: also B I think.
Hope this helps.
Given:
m = 52 kg. the mass of water
ΔT = 22 °C, the temperature increase
Note that
c = 4.184 J/(g-°C), the specific heat of water.
The quantity of heat required is
Q = mcΔT
= (52,000 g)*(4.184 J/(g-°C))*(22 °C)
= 4.7865 x 10⁴ J
Because 1 J = 2.39 x 10⁻⁴ cal. the heat required is
Q = (4.7865 x 10⁴ J)*(2.39 x 10⁻⁴ cal/J) = 1143.97 cal ≈ 1144 cal
Answer: 1144 cal
Answer:
1
Explanation:
For non metals to attain a noble gas configuration, they gain the number of electrons needed to attain the noble gas configuration of the noble gas at the end of their periods. This means that these non metals would only take up the configuration of the last element on their periods which of course is always a noble gas.
The last element on the hydrogen period or more conservatively the only other element on the hydrogen period is helium, with an atomic number of 2. The atomic number is the number of protons in he nucleus of an atom. For an electrically neutral atom, the number of electrons equal the number of protons.
Hence we can deduce that helium has 2 electrons while hydrogen has one electron. Thus for it to attain the configuration of helium, it just needs to gain one more electron