Answer:
8-0!/
Explanation:
A. 0.67 m/s² forward
F applied = 250 N
Fsin30 = 250/2 = 125N
F friction= 95 N
Fnet = F app - F fri
= 125-95
= 30 N ( forward)
Fnet = m a
30 = 45 a
a= 30/45
=2/3
= 0.67 m/s² (forward)