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2 years ago

How old is a bone if it still has 50% of its carbon-14 content?

Physics

1 answer:

Degger [83]2 years ago

6 0

Answer:

5730 years

Explanation:

The half life of carbon-14 is 5730 years. If 50% of the carbon-14 remains, then exactly 1 half life has passed.

The half-life equation is:

A = A₀ (½)^(t / T)

where A is the remaining amount,

A₀ is the initial amount,

t is time,

and T is the half life.

In this case, A = ½ A₀ and T = 5730.

½ A₀ = A₀ (½)^(t / 5730)

½ = (½)^(t / 5730)

1 = t / 5730

t = 5730

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OverLord2011 [107]

Answer:

The phase difference is $\Delta \phi = 1.9995 rad$

Explanation:

From the question we are told that

The distance between the loudspeakers is $d = 2m$

The distance of the listener from the wall $D = 81.7 \ m$

The frequency of the loudspeakers is $f = 4450Hz$

The velocity of sound is $v_s = 343 m/s$

The path difference of the sound wave that is getting to the listener is mathematically represented as

$\Delta z =\sqrt{d^2 + D^2} -D$

Substituting values

$\Delta z =\sqrt{2^2 + 81.7^2 } -81.7$

$\Delta z =0.0245m$

The phase difference is mathematically represented as

$\Delta \phi$ = $\frac{2 \pi}{\lambda } * \Delta z$

Where $\lambda$ is the wavelength which is mathematically represented as

$\lambda = \frac{v_s }{f}$

substituting value

$\lambda = \frac{343 }{4450}$

$\lambda = 0.0770 m$

Substituting value into the equation for phase difference

$\Delta \phi$ = $\frac{2 * 3.142 * 0.0245}{0.0770}$

$\Delta \phi = 1.9995 rad$

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3 years ago

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Andre45 [30]

Answer:

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Explanation:

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vivado [14]

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Learn more about fossil here: brainly.com/question/11829803

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laila [671]

Answer:

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