Answer:
The 1470 kJ of energy supplied by the yogurt would be consumed by 150 W of work (efficiency of 20%) in about 32.7 h. Then if people is not careful, easily would have more energy from the food that the amount that can consume exercising.
Explanation:
Step 1.
- Energy supplied: 1470 kJ = 1470000 J.
- Rate of energy used for the : 150 W = 150 J/s. <em>This means that each second of this kind of work requieres 150 J of energy,</em>
Step 2
For this case, efficiency is defined as the relationship between the actual rate of energy used, to the rate of energy consumed to obtain it. So:

Then the rate of energy required for this work, is calculated solving for
:

<em>This means that for a work that as a rate of 150 J/s , It requieres to consume energy at a rate of 750 J/s.</em>
Step 3
Now, it is possible to calculate how much time would be needed to consume the 1470000 J of energy of the yogurt. It done using this relationship:

Where Energy stands for the total amount of energy that would be consumed, and rate stans for the rate of energy consumption, Then the time would be:

Then if for the consumption of 1470 kJ of energy is required almost 33 hours, Then is easy to see that the amount of enegy that can be obtain of food would much more than the amount that can be depleted by exercise
If their are choices you should list them. The givens are pretty specific though.
W = E * I is the answer
E (voltage) = W/I is a more refined answer. <<< answer.
Answer:
I would say false
Explanation:
Because friction slows it down which means when the object bounces back it will not have the same energy or force that was applied before.
Answer:
Explanation:
Power = Energy/time
-Don't have energy so I'm gonna solve for it
Gravitational Potential Energy = mass x gravity x height
= 60 kg x 9.8 m/s2 x 5m
= 2940 J
Power = Energy/time
=2940 J/10 s
= 294 W
Answer:
The answer to the question is 2.2khz
Explanation:
<em>Let z₁ = 5.4m</em>
<em>Let z₂ = 4.6m</em>
<em>The path difference Δz = z₁-z₂ = 5.4 - 4.6 = 0.8m</em>
<em>For the interference= Δz λ, 2λ, 3λ......</em>
<em>The wavelength λ = 0.8m</em>
<em>The speed of sound v = 344m/s</em>
<em>The frequency f = v/λ = 344/0.8 = 430hz</em>
<em>Now,</em>
<em>f₁ =f, f₂= 2f, f₃ = 3f, f₄= 4f, f₅ =5f which is,</em>
<em>f₁ =f = 430Hz, f₂=2f =860Hz, f₃ =3f =1290Hz f₄ =4f =1720Hz and f₅=5f =2150Hz</em>
<em>f5 = 2120Hz = 2.200Hz </em>
<em>we will convert to two significant figures =2.2kHz</em>
<em> </em>