The photo shows a system that consists of a person on a diving board. What change could you make to the system that would decrea
se its total energy?
A. Replace the diver with someone who has more mass.
B. Decrease the height of the diving board.
C. Increase the length of the diving board.
D. Increase the height of the diving board.
*If you do not know the answer, then DON'T respond. I will report you. Also, explanations are appreciated but if not then that's fine.
A. Replace the diver with someone who has more mass.
B. Decrease the height of the diving board.
C. Increase the length of the diving board.
D. Increase the height of the diving board.
*If you do not know the answer, then DON'T respond. I will report you. Also, explanations are appreciated but if not then that's fine.
2 answers:
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Answer:
A half-life is the time required for one half of the nuclei in a radio- active isotope to decay.
Explanation:
A radio-active isotope is an isotope which undergoes radioactive decay.
Radioactive decay is a spontaneous process in which the nucleus of an atom changes its state (turning into a different nucleus, or de-exciting), emitting radiation, which can be of three different types: alpha, beta or gamma.
The half-life of a radio-active isotope is the time required for half of the nuclei of the initial sample to decay.
The law of radio-active decay can be expressed as follows:
where
N(t) is the number of undecayed nuclei left at time t
N0 is the initial number of nuclei
t is the time
is the half-life
We see that when (that means, when 1 half-life has passed), the number of undecayed nuclei left is
So, half of the initial nuclei.
Answer:
(a) 62.69 nJ/m^3
(b) 1015.22 μJ/m^3
Explanation:
Electric field, E = 119 V/m
Magnetic field, B = 5.050 x 10^-5 T
(a) Energy density of electric field =
= 6.269 x 10^-8 J/m^3 = 62.69 nJ/m^3
(b) energy density of magnetic field =
= 1.01522 x 10^-3 J/m^3 = 1015.22 μJ/m^3