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fgiga [73]
3 years ago
10

What countries do not use the metric system?

Mathematics
1 answer:
Georgia [21]3 years ago
4 0
Burma,Liberia<span> and the </span><span>United States</span>
You might be interested in
The Baker Family spent $28 on 5 tickets.
White raven [17]

Answer:

I cannot not give the correct solution, need more context. How many children are there, how many adults are in the family? So I will explain in my explanation.

Step-by-step explanation:

If more context were given, for example:<em> 2 adults and 2 children.</em>

Then the bakers would have bought 2 adult tickets for ___ each

Then the bakers would have bought 3 children's tickets for ___ each

So using what we know we can create an equation:

<em>2A+3C=28</em>,<em> </em>

meaning 2 adult tickets plus 3 children's tickets costs a total of $28.

So we divide 28 by 5, which is the total amount of tickets.

28/5=5.6

So to figure the cost of children's tickets multiply the cost by amount.

3*$5.6=$16.8, C=16.8

To figure out the cost of the adults tickets multiple the cost by the amount.

2*$5.6=$11.2, A=11.2

a) the bakers would have bought <u>2</u> adult tickets for <u>5.6</u> each.

b) the bakers would have bought <u>3</u> children's tickets for <u>5.6</u> each.

8 0
3 years ago
Rosetta wants to estimate the percentage of people who rent their home. She surveys 250 individuals and finds that 48 rent their
Andreas93 [3]

Answer:

0.192 - 1.645\sqrt{\frac{0.192(1-0.192)}{250}}=0.151

0.192 + 1.645\sqrt{\frac{0.192(1-0.192)}{250}}=0.233

Step-by-step explanation:

Information given

X= 48 number of people who rent their home

n= 250 represent the sample size

\hat p =\frac{48}{250}= 0.192 represent the proportion of people who rent their home

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 90% of confidence, our significance level would be given by \alpha=1-0.90=0.1 and \alpha/2 =0.05. And the critical value would be given by:

z_{\alpha/2}=\pm 1.645

The confidence interval for the mean is given by the following formula:  

\hat p \pm z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}

If we replace the values obtained we got:

0.192 - 1.645\sqrt{\frac{0.192(1-0.192)}{250}}=0.151

0.192 + 1.645\sqrt{\frac{0.192(1-0.192)}{250}}=0.233

3 0
3 years ago
Round 5049 correct to 1 significant figure​
Step2247 [10]

5000

  • Addition (+) and subtraction (-) round by the least number of decimals.
  • Multiplication (* or ×) and division (/ or ÷) round by the least number of significant figures.
  • Logarithm (log, ln) uses the input's number of significant figures as the result's number of decimals.
  • Antilogarithm (n^x.y) uses the power's number of decimals (mantissa) as the result's number of significant figures.
  • Exponentiation (n^x) only rounds by the significant figures in the base.
  • To count trailing zeros, add a decimal point at the end (e.g. 1000.) or use scientific notation (e.g. 1.000 × 10^3 or 1.000e3).
  • Zeros have all their digits counted as significant (e.g. 0 = 1, 0.00 = 3).
  • Rounds when required, after parentheses, and on the final step.

<em>-</em><em> </em><em>BRAINLIEST </em><em>answerer</em><em> ❤️</em>

7 0
2 years ago
Read 2 more answers
Suppose a triangle has sides a, b, and c, and the angle opposite the side of length a is acute. What must be true?
Ket [755]
3pi/7 < pi/2 because 3/7 < 1/2, and pi/2 is a right angle. Conclusion: the angle opposite side a is an acute angle. In this situation the triangle could be a right triangle, in which case C would be true, but it does not have to be a right triangle, so don´t choose C. Similarly, it could be an acute triangle, in which case B would be true, but it does not have to be, so don´t choose B. Also, A says the angle opposite side a is obtuse, which is false. So don´t choose A. That leaves D, which says the angle opposite side a is acute, which we know is true. So the answer is <span>D. b^2 + c^2 > a^2</span>
4 0
3 years ago
A blackjack player at a Las Vegas casino learned that the house will provide a free room if play is for four hours at an average
marysya [2.9K]

Answer:

a) player’s expected payoff is $ 240

b) probability the player loses $1000 or more is 0.1788

c)  probability the player wins is 0.3557

d) probability of going broke is 0.0594

Step-by-step explanation:

Given:

Since there are 60 hands per hour and the player plays for four hours then the sample size is:

n = 60 * 4 = 240

The player’s strategy provides a probability of .49 of winning on any one hand so the probability of success is:

p = 0.49

a)

Solution:

Expected payoff is basically the expected mean

Since the bet is $50 so $50 is gained when the player wins a hand and $50 is lost when the player loses a hand. So

Expected loss =  μ

                        = ∑ x P(x)

                        = 50 * P(win) - 50 * P(lose)

                        = 50 * P(win) + (-50) * (1 - P(win))

                         = 50 * 0.49 - 50 * (1 - 0.49)

                        = 24.5 - 50 ( 0.51 )

                        = 24.5 - 25.5

                        = -1

Since n=240 and expected loss is $1 per hand then the expected loss in four hours is:

240 * 1 = $ 240

b)

Using normal approximation of binomial distribution:

n = 240

p = 0.49

q = 1 - p = 1 - 0.49 = 0.51

np = 240 * 0.49 = 117.6

nq = 240 * 0.51 = 122.5

both np and nq are greater than 5 so the binomial distribution can be approximated by normal distribution

Compute z-score:

z = x - np / √(np(1-p))

  = 110.5 - 117.6 / √117.6(1-0.49)

  = −7.1/√117.6(0.51)

  = −7.1/√59.976

  = −7.1/7.744417

  =−0.916789

Here the player loses 1000 or more when he loses at least 130 of 240 hands so the wins is 240-130 = 110

Using normal probability table:

P(X≤110) = P(X<110.5)

             = P(Z<-0.916)

             = 0.1788

c)

Using normal approximation of binomial distribution:

n = 240

p = 0.49

q = 1 - p = 1 - 0.49 = 0.51

np = 240 * 0.49 = 117.6

nq = 240 * 0.51 = 122.5

both np and nq are greater than 5 so the binomial distribution can be approximated by normal distribution

Compute z-score:

z = x - np / √(np(1-p))

  = 120.5 - 117.6 / √117.6(1-0.49)

  = 2.9/√117.6(0.51)

  = 2.9/√59.976

  = 2.9/7.744417

  =0.374463

Here the player wins when he wins at least 120 of 240 hands

Using normal probability table:

P(X>120) = P(X>120.5)

              = P(Z>0.3744)  

             =  1 - P(Z<0.3744)

             = 1 - 0.6443

             = 0.3557

d)

Player goes broke when he loses $1500

Using normal approximation of binomial distribution:

n = 240

p = 0.49

q = 1 - p = 1 - 0.49 = 0.51

np = 240 * 0.49 = 117.6

nq = 240 * 0.51 = 122.5

both np and nq are greater than 5 so the binomial distribution can be approximated by normal distribution

Compute z-score:

z = x - np / √(np(1-p))

  = 105.5 - 117.6 / √117.6(1-0.49)

  = -12.1/√117.6(0.51)

  = -12.1/√59.976

  = -12.1/7.744417

  =−1.562416

Here the player loses 1500 or more when he loses at least 135 of 240 hands so the wins is 240-135 = 105

Using normal probability table:

P(X≤105) = P(X<105.5)

             = P(Z<-1.562)

             = 0.0594

7 0
3 years ago
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