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3 years ago

Which statement best summarizes the importance of Ernest Rutherford’s gold foil experiment?

2 answers:

8 0

<span>It showed that a nucleus occupies a small part of the whole atom. The fact that most of the particles passes right through the gold foil indicated that the actual volume of the nucleus is incredibly small compared to the size of the atom since the nucleus is what would stop the particles from passing through it.</span>

Elena-2011 [213]3 years ago

6 0

Answer:

<h2>D. It showed that a nucleus occupies a small part of the whole atom.</h2>

Explanation:

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Pl help it’s for a grade I will give you Brainly

Inessa [10]

Answer:

D. B, C, A

Explanation:

A. For object A, given the following data;

Mass = 2kg

Net force = 1N

To find the acceleration;

Acceleration = net force/mass

Acceleration = 1/2

<em>Acceleration = 0.5m/s²</em>

B. For object B, given the following data;

Mass = 8kg

Net force = 10N

To find the acceleration;

Acceleration = net force/mass

Acceleration = 10/8

<em>Acceleration = 1.25m/s²</em>

C. For object C, given the following data;

Mass = 7kg

Net force = 7N

To find the acceleration;

Acceleration = net force/mass

Acceleration = 7/7

<em>Acceleration = 1m/s²</em>

Therefore, placing the objects in decreasing order, according to the magnitude of the acceleration they are experiencing is B, C, A

8 0

3 years ago

Fill in the blanks with the words given below-

ioda

Answer:

1. Metal.

2. Atom.

3. Homogeneous

4. Compounds.

5. Lustrous

6. Saturated.

7. Colloidal; true.

8. Homogeneous.

Explanation:

1. An element which are sonorous are called metal.

2. An element is made up of only one kind of atom.

3. Alloys are homogeneous mixtures.

4. Elements chemically combines in fixed proportion to form compounds.

5. Metals are lustrous and can be polished.

6. A solution in which no more solute can be dissolved is called a saturated solution.

7. Milk is a colloidal solution but vinegar is a true solution.

8. A solution is a homogeneous mixture.

8 0

3 years ago

aqueous lithium hydroxide solution is used to purify air (remove co2) in spacecrafts and submarines. the pressure of carbon diox

oksano4ka [1.4K]

The mass of the water is 1580 g.

<h3>What is the amount of water formed?</h3>

We know that the ideal gas equation can be used to obtain the number of moles of the gas. We have been told that the pressure of the gas reduced from 7.9 x 10-3 atm to 1.2 x 10-4 atm. The change in pressure can be used obtain the number of moles.

Change in pressure = 7.9 x 10-3 - 1.2 x 10-4 = 7.78 * 10^-3 atm

Using;

PV = nRT

n = PV/RT

n = 7.78 * 10^-3 atm * 2.4 x10^5 l/0.082 * (39 + 273)

n = 85 moles

Since 1 mole of carbon dioxide produces 1 mole of water

85 moles of carbon dioxide produces 85 mole of water

Mass of water produced = 85 mole * 18 g/mol

= 1580 g

Learn more about ideal gas equation:brainly.com/question/4147359

#SPJ1

6 0

1 year ago

A 73.6 g sample of aluminum is heated to 95.0°C and dropped into 100.0 g of water at 20.0°C. If the resulting temperature of the

Softa [21]

Answer:

The specific heat of aluminium is 0.875 J/g°C

Explanation:

Step 1: Data given

The mass of the aluminium sample = 73.6 grams

Initial temperature of the sample = 95.0 °C

Mass of water = 100.0 grams

Initial temperature of water = 20.0 °C

Final temperature of water and aluminium = 30.0 °C

The specific heat of water = 4.184 J/g°C

Step 2: Calculate the specific heat of aluminium

Q gained = Q lost

Qwater = -Qaluminium

Q = m*c*ΔT

m(aluminium) * c(aluminium) * ΔT(aluminium) = - m(water) * c(water) * ΔT(aluminium)

⇒ mass of aluminium = 73.6 grams

⇒ c(aluminium) = TO BE DETERMINED

⇒ ΔT(aluminium) = The change of temperature = T2 - T1 = 30 .0 °C - 95.0 °C = -65.0°C

⇒ mass of water = 100.0 grams

⇒ c(water ) = The specific heat of water = 4.184 J/g°C

⇒ ΔT(water) = The change of temperature of water = T2 - T1 = 30.0 - 20.0 = 10.0 °C

73.6g * c(aluminium) * -65.0 °C = 100.0g * 4.184 J/g°C * 10.0°C

-4784 * c(aluminium) = -4184

c(aluminium) = 0.875 J /g°C

The specific heat of aluminium is 0.875 J/g°C

7 0

3 years ago

At 850K, 65L of gas has a pressure of 450kPa. What is the volume (in liters) if the gas is cooled to 430K and the pressure decre

Novosadov [1.4K]

Answer:

V₂ = 45.53 L

Explanation:

Given data:

Initial temperature = 850 K

Initial volume = 65 L

Initial pressure = 450 KPa

Final temperature = 430 K

Final pressure = 325 KPa

Final volume = ?

Solution:

Formula:

P₁V₁/T₁ = P₂V₂/T₂

P₁ = Initial pressure

V₁ = Initial volume

T₁ = Initial temperature

P₂ = Final pressure

V₂ = Final volume

T₂ = Final temperature

Solution:

V₂ = P₁V₁ T₂/ T₁ P₂

V₂ = 450 KPa× 65 L × 430 K / 850 K × 325KPa

V₂ = 12577500 KPa .L. K / 276250 K. KPa

V₂ = 45.53 L

8 0

3 years ago