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pav-90 [236]
3 years ago
6

Which statement best summarizes the importance of Ernest Rutherford’s gold foil experiment?

Chemistry
2 answers:
diamong [38]3 years ago
8 0
<span>It showed that a nucleus occupies a small part of the whole atom.  The fact that most of the particles passes right through the gold foil indicated that the actual volume of the nucleus is incredibly small compared to the size of the atom since the nucleus is what would stop the particles from passing through it.</span>
Elena-2011 [213]3 years ago
6 0

Answer:

<h2>D. It showed that a nucleus occupies a small part of the whole atom.</h2>

Explanation:

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In a hotel breakfast bar you see an older woman sticking a fork into a toaster to remove a piece of toast. You wamn her not to d
hram777 [196]

Answer: I guess have to like explain to her why to not stick the fork into the toaster.

Explanation:

Hope this helps

5 0
3 years ago
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Liquid nitrogen has a density of 0.808 g/mL and boils at 77 K. Researchers often purchase liquid nitrogen in insulated 195-L tan
Reika [66]

Answer:

The nswer to the question is

The maximum fraction of the air in the room that could be displaced by the gaseous nitrogen is 0.548 or 54.8 %

Explanation:

To solve the question we note that

The density of the liquid nitrogen = 0.808g/mL and the volume is 195 L tank (vaporised)

Therefore since density = mass/volume we have

mass = Density × volume = 0.808 g/mL × 195 L × 1000 ml/L =157560 g

In gaseous form the liquid nitrogen density =1.15 g/L

That is density = mass/volume and volume = mass/density = 157560 g/(1.15g/L)  or

volume = 137008.69565 L

The dimension of the room = 10 m × 10 m × 2.5 m = 250 m³ and

1 m³ is equivalent to 1000 L, therefore 250 m³ = 250 m³  × 1000 L/m³ = 250000L

Therefore fraction of the volume occupied by the gaseous nitrogen =

137008.69565 L/250000 L = 0.548

Therefore the gaseous nitrogen occpies 54.8% of the room

7 0
3 years ago
The standard free energy of activation of one reaction A is 95.00 kJ mol–1 (22.71 kcal mol–1). The standard free energy of activ
diamong [38]

Answer:

The answer to the questions are as follows

Reaction B is 4426.28 times faster than reaction A

(b) Reaction B is faster.

Explanation:

To solve the question we are meant to compare both reactions to see which one is faster

The values of the given activation energies are as follows

For A

Ea = 95.00 kJ mol–1 (22.71 kcal mol–1) and

for  B

Ea = 74.20 kJ mol–1 (17.73 kcal mol–1)

T is the same for both reactions and is equal to 298 k

Concentration of both reaction = 1M

The Arrhenius Law is given by

k = Ae^{\frac{-E_{a} }{RT} }

Where

k = rate constant

Ea = activation energy

R = universal gas constant

T = temperature  (Kelvin )

A = Arrhenius factor

Therefore

For reaction A, the rate constant k₁ is given by k₁ = Ae^{\frac{-95000}{(8.314)(298)} }

And for B the rate constant k₂ is given by k₂ = Ae^{\frac{-74200 }{(8.314)(298)} }

k₁ = A×2.225×10⁻¹⁷

k₂ = A×9.850×10⁻¹⁴

As seen from the above Reaction B is faster than reaction A by (A×9.850×10⁻¹⁴)/(A×2.225×10⁻¹⁷) or 4426.28 times

3 0
3 years ago
A steel container filled with H₂ gas is at a pressure of 6.5 atm and a temperature of 22°C. If the container is placed near a fu
Yuki888 [10]

Answer: The new pressure is 7.1 atm

Explanation:

To calculate the final pressure of the system, we use the equation given by Gay-Lussac Law. This law states that pressure of the gas is directly proportional to the temperature of the gas at constant pressure.

Mathematically,

\frac{P_1}{T_1}=\frac{P_2}{T_2}

where,

P_1\text{ and }T_1 are the initial pressure and temperature of the gas.

P_2\text{ and }T_2 are the final pressure and temperature of the gas.

We are given:

P_1=6.5atm\\T_1=22^0C=(22+273)K=295K\\P_2=?\\T_2=50^0C=(50+273)K=323K

Putting values in above equation, we get:

\frac{6.5}{295}=\frac{P_2}{323}\\\\P_2=7.1

Hence, the new pressure is 7.1 atm

8 0
3 years ago
Creatinine, �!�!�!�, is a by-product of muscle metabolism, and creatinine levels in the body are known to be a fairly reliable i
Inessa05 [86]

Answer:

Explanation:

molecular weight of creatinine = 131

1 mg of creatinine = 1 x 10⁻³ / 131 = 7.63 x 10⁻⁶ mole of creatinine.

volume of solution = .1 L

mass of blood solution = .1 x 1025

= 102.5 g

mass of solvent = 102.5 g approximately

= .1025 kg

molality = mole of solute / mass of solvent in kg

= 7.63 x 10⁻⁶ / .1025 kg

= 74.44 x 10⁻⁶ .

Osmotic pressure :---

π V / T = nR     π is  osmotic pressure , V is volume of solution in liter , T is absolute temperature , n is molality .

π x .1 / 298 =  74.44 x 10⁻⁶ x .082

π = 18.19 x 10⁻³ atm

7 0
3 years ago
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