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grandymaker [24]
3 years ago
11

What is the molarity of an aqueous solution containing 1.5 moles of calcium chloride in 2.75 L of solution? A. 0.004 M B. 0.55 M

C. 1.83 M D. 4.13 M
Chemistry
1 answer:
kondor19780726 [428]3 years ago
6 0

Answer:

B. 0.55 M

Explanation:

Step 1: Given data

  • Moles of calcium chloride (solute): 1.5 mol
  • Volume of solution: 2.75 M

Step 2: Calculate the molarity of the aqueous solution

The molarity is a way to express the concentration of a solution. It is equal to the quotient between the moles of solute and the liters of solution.

M = moles of solute / liters of solution

M = 1.5 mol / 2.75 L = 0.55 mol/L = 0.55 M

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Which of the following will occur soon after a population of prey increases slightly in size?
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4 years ago
The rate law for the reaction 2A + B →C is –rA= kACA2CBwithkA= 25 (L/mol)2sec. What arekBandkC?
givi [52]

Explanation:

The given reaction equation is as follows.

             2A + B \rightarrow C

So, rate constants for different reactants and products written as follows.

             \frac{-k_{A}}{\text{stoichiometric coefficient of A}} = \frac{-k_{B}}{\text{stoichiometric coefficient of B}} = \frac{k_{C}}{\text{stoichiometric coefficient of C}}

As per the reaction equation, the stoichiometric coefficients of reactants and products are as follows.

         A = -2

         B = -1

         C = 1

Therefore,

      \frac{-k_{A}}{\text{stoichiometric coefficient of A}} = \frac{-k_{B}}{\text{stoichiometric coefficient of B}} = \frac{k_{C}}{\text{stoichiometric coefficient of C}}

      \frac{-k_{A}}{-2} = \frac{-k_{B}}{-1} = \frac{k_{C}}{1}    

             \frac{-k_{A}}{-2} = k_{B} = k_{C}

Hence,          k_{B} = k_{C} = \frac{25}{2} (L/mol)^{2}

                                          = 12.5 (L/mol)^{2}

Thus, we can conclude that k_{B} and k_{C} are 12.5 (L/mol)^{2}.

5 0
3 years ago
Can an ion be either positive or negative? True or False
vekshin1

Answer:

True

Explanation:

3 0
3 years ago
typical seawarer contains 2.7g of salt (sodium chloride,Nacl)per 100ml (100*10-3L).what is the molarity of Nacl in the ocean?​
faust18 [17]

Answer:

Molarity = 0.5 M

Explanation:

Given data:

Mass of NaCl = 2.7 g

Volume = 100 mL(100×10⁻³L)

Molarity of solution = ?

Solution:

Formula:

Molarity = number of moles / volume in litter

Number of moles:

Number of moles = mass/ molar mass

Number of moles = 2.7 g/ 58.5 g/mol

Number of moles = 0.05 mol

Molarity = number of moles / volume in litte

Molarity = 0.05 mol / 100×10⁻³L

Molarity = 0.5 M

4 0
3 years ago
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