Read the given equation. 2Na + 2H2O → 2NaOH + H2
1 answer:
Answer:
B) 12.9 grams.
Explanation:
How many moles of molecules in that 6.30 L of H₂?
The volume of one mole of an ideal gas at STP (0 °C, 1 atm) is 22.4 liters.
(The volume of that one mole of gas at STP will be 22.7 liters if STP is defined as 0 °C and 10⁵ Pa).
.
How many moles of Na will be needed?
The coefficient in front of Na in the equation is twice the coefficient in front of H₂. It takes two moles of Na to produce one mole of H₂.
.
What's the mass of that many Na atoms?
Refer to a modern periodic table. The molar mass of ₁₁Na is 22.990. The mass of one mole of Na atoms is 22.990 gram. The mass of 0.5625 moles of Na atoms will be
.
(2 sig. fig. as in the volume of the H₂ gas.)
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Answer:
<h2>117.94 moles</h2>Explanation:
To find the number of moles in a substance given it's number of entities we use the formula
where n is the number of moles
N is the number of entities
L is the Avogadro's constant which is
6.02 × 10²³ entities
From the question we have
We have the final answer as
<h3>117.94 moles</h3>Hope this helps you
Answer : The percent yield of the reaction is, 75.6 %
Solution : Given,
Mass of Pb = 451.4 g
Molar mass of Pb = 207 g/mole
Molar mass of PbO = 223 g/mole
First we have to calculate the moles of Pb.
Now we have to calculate the moles of
The balanced chemical reaction is,
From the reaction, we conclude that
As, 2 mole of react to give 2 mole of
So, 2.18 mole of react to give 2.18 mole of
Now we have to calculate the mass of
Theoretical yield of = 486.1 g
Experimental yield of = 367.5 g
Now we have to calculate the percent yield of the reaction.
Therefore, the percent yield of the reaction is, 75.6 %