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Veseljchak [2.6K]
3 years ago
7

at a certain pressure the density of superficial carbon dioxide is 0.469. what is the mass of a 25.0 mL sample of supercritical

carbon dioxide at this pressure?
Chemistry
1 answer:
Murrr4er [49]3 years ago
7 0

Answer:

\large \boxed{\text{11.7 g}}

Explanation:

\text{Mass} = \text{25.0 mL} \times \dfrac{\text{0.469 g}}{\text{1 mL}} = \textbf{11.7 g}\\\\\text{The mass of the carbon dioxide is $\large \boxed{\textbf{11.7 g}}$}

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Answer:

C) ball rollinflown a hill

Explanation:

The question asks to  identify the endothermic process in the list of options. By way of elimination, we have;

A) condensation of water on a wind shield of a car

Condensation is an exothermic process. That is, heat is given out as the gases change into the liquid state of matter.

B) formation of copper

This is an exothermic process. Capture of electrons by a cation is always exothermic.

C) ball rollinflown a hill

This is the correct option. Energy is absorbed by the ball as it moves on the hill

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Freezing is an example of exothermic reaction. Heat is given off to the surroundings.

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What mass of HCL, in grams, is required to react with 0.610 g of al(oh)3 ?
kompoz [17]

Answer: 0.8541 grams of HCl will be required.

Explanation: Moles can be calculated by using the formula:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}

Given mass of Al(OH)_3 = 0.610 g

Molar mass of Al(OH)_3 = 78 g/mol

\text{Number of moles}=\frac{0.610g}{78g/mol}

Number of moles of Al(OH)_3 = 0.0078 moles

The reaction between Al(OH)_3 and HCl is a type of neutralization reaction because here acid and base are reacting to form an salt and also releases water.

Chemical equation for the above reaction follows:

Al(OH)_3+3HCl\rightarrow AlCl_3+3H_2O

By Stoichiometry,

1 mole of  Al(OH)_3 reacts with 3 moles of HCl

So, 0.0078 moles of Al(OH)_3 will react with \frac{3}{1}\times 0.0078 = 0.0234 moles

Mass of HCl is calculated by using the mole formula, we get

Molar mass of HCl = 36.5 g/mol

Putting values in the equation, we get

0.0234moles=\frac{\text{Given mass}}{36.5g/mol}

Mass of HCl required will be = 0.8541 grams

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