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Veseljchak [2.6K]
2 years ago
7

at a certain pressure the density of superficial carbon dioxide is 0.469. what is the mass of a 25.0 mL sample of supercritical

carbon dioxide at this pressure?
Chemistry
1 answer:
Murrr4er [49]2 years ago
7 0

Answer:

\large \boxed{\text{11.7 g}}

Explanation:

\text{Mass} = \text{25.0 mL} \times \dfrac{\text{0.469 g}}{\text{1 mL}} = \textbf{11.7 g}\\\\\text{The mass of the carbon dioxide is $\large \boxed{\textbf{11.7 g}}$}

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Explain what "LEO the lion goes GER" means based upon what you have learned
olchik [2.2K]

"LEO the lion goes GER" means based upon the oxidation and reduction reactions.

<h3>What is oxidation and reduction reaction?</h3>

Oxidation reactions are those reactions in which lossing of electrons are taking place from the substrate molecule and in reduction process gaining of electrons is done by substrate molecules.

The phrase "LEO the lion goes GER" is used in the context of oxidation and reduction reactions. Meaning of the terms:
LEO → Lose electrons = oxidation

GER → Gain electrons = reduction

Hence the given line is based on oxidation and reduction.

To know more about oxidation and reduction, visit the below link:
brainly.com/question/4222605

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2 years ago
Compounds have physical properties that
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The answer is B, they differ greatly from the properties of all their elements. For example: Water is non-flamable but it is made from hydrogen, which is highly flammable, and oxygen, a gas that supports combustion.
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What are some gases that dissolve in water?
maksim [4K]

Explanation:

The main gases dissolved in purified water are oxygen and nitrogen, carbon dioxide, plus traces of inert gases, all in equilibrium with ambient air.

5 0
2 years ago
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Which of the following would result in being able to dissolve a greater amount of gas in a solution? ​
makkiz [27]

Answer:

Lower the temperature of the solution

8 0
3 years ago
What is the empirical formula for a compound if 300.00 g of it is known to contain 82.46224 g of molybdenum, 45.741 g of chlorin
Marysya12 [62]

Answer:

MoClBr₂

Explanation:

First we calculate the mass of bromine in the compound:

  • 300.00 g - (82.46224 g + 45.741 g) = 171.79676 g

Then we<u> calculate the number of moles of each element</u>, using their <em>respective molar masses</em>:

  • 82.46224 g Mo ÷ 95.95 g/mol = 0.9594 mol Mo
  • 45.741 g Cl ÷ 35.45 g/mol = 1.290 mol Cl
  • 171.79676 g Br ÷79.9 g/mol = 2.150 mol Br

Now we <u>divide those numbers of moles by the lowest number among them</u>:

  • 0.9594 mol Mo / 0.9594 = 1
  • 1.290 mol Cl / 0.9594 = 1.34 ≅ 1
  • 2.150 mol Br / 0.9594 = 2.24 ≅ 2

Meaning the empirical formula is MoClBr₂.

8 0
3 years ago
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