D: The atomic mass number
The number of moles of gas lost is 0.0213 mol. It can be solved with the help of Ideal gas law.
<h3>What is Ideal law ?</h3>
According to this law, "the volume of a given amount of gas is directly proportional to the number on moles of gas, directly proportional to the temperature and inversely proportional to the pressure. i.e.
PV = nRT.
Where,
- p = pressure
- V = volume (1.75 L = 1.75 x 10⁻³ m³)
- T = absolute temperature
- n = number of moles
- R = gas constant, 8.314 J*(mol-K)
Therefore, the number of moles is
n = PV / RT
State 1 :
- T₁ = (25⁰ C = 25+273 = 298 K)
- p₁ = 225 kPa = 225 x 10³ N/m²
State 2 :
- T₂ = 10 C = 283 K
- p₂ = 185 kPa = 185 x 10³ N/m²
The loss in moles of gas from state 1 to state 2 is
Δn = V/R (P₁/T₁ - P₂/T₂ )
V/R = (1.75 x 10⁻³ m³)/(8.314 (N-m)/(mol-K) = 2.1049 x 10⁻⁴ (mol-m²-K)/N
p₁/T₁ = (225 x 10³)/298 = 755.0336 N/(m²-K)
p₂/T₂ = (185 x 10³)/283 = 653.7102 N/(m²-K)
Therefore,
Δn = (2.1049 x 10⁻⁴ (mol-m²-K)/N)*(755.0336 - 653.7102 N/(m²-K))
= 0.0213 mol
Hence, The number of moles of gas lost is 0.0213 mol.
Learn more about ideal gas here ;
https://brainly.in/question/641453
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Answer:
strength = 10⁻²/10⁻³ = 10 times more acidic
Explanation:
1. A solution with a pH of 9 has a pOH of
pH + pOH = 14 => pOH = 14 - pH = 14 - 9 = 5
2. Which is more acidic, a solution with a pH of 6 or a pH of 4?
pH of 4 => Higher [H⁺] = 10⁻⁴M vs pH of 6 => [H⁺] = 10⁻⁶M
3. How many times more acidic is a solution with a pH of 2 than a solution with a pH of 3?
soln with pH = 2 => [H⁺] = 10⁻²M
soln with pH = 3 => [H⁺] = 10⁻³M
strength = 10⁻²/10⁻³ = 10 times more acidic
4. What is the hydrogen ion concentration [H + ] in a solution that has a pH of 8?
[H⁺] = 10^-pH = 10⁻⁸M
5. A solution has a pOH of 9.6. What is the pH? (Use the formula.)
pH + pOH = 14 => pH = 14 - 9.6 = 4.4
