Answer:
Explanation:
Hello.
In this case, we can see that the mass of carbon of the unknown compound comes from the yielded mass of carbon dioxide, thus, we compute the moles of carbon as follows:
Moreover, the mass of hydrogen comes from the yielded water, therefore we can also compute the moles of water:
Then, to find the subscripts in the empirical formula, we divide by the moles of carbon as the smallest:
Whose molar mass is:
Thus, the ratio of the molecular formula to the empirical formula is:
Therefore, the molecular formula is twice the empirical formula:
Which is actually ethane.
Regards.
Answer:
1. Heterogeneous: Mixtures in which composition is not uniform throughout. For example, soil.
2. Homogeneous: Mixtures that have uniform composition throughout. For example, air.
3. Solute: the component of a solution which is present in smaller quantity. For example, Sugar in water
4. Solvent: the component of a solution which is pr3esent in larger quantity. For example, water
5. Solution: A solution is a homogeneous mixture of two or more substances. For example brass.
6. Mixture: When two or more compounds or elements mix up physically they from a mixture.
7. Colloid: Solutions in which particles are large and possess the characteristics of the Tyndall effect. For example milk.
8. Dissociation: the splitting of a molecule into smaller molecules is called dissociation.
9. Pure substance: A pure substance is a type of matter having definite properties.
10. Suspension: Suspensions are heterogeneous mixtures of undissolved particles. For example milk of magnesia.
11. Element: element is a substance made up of the same number of atoms.For example hydrogen
12. Compound: Compound is a substance made up of two or more elements. For example water.
Answer:
, Kp = 0.08967
, Kp = 2.3×10³⁰
Explanation:
The relation between Kp and Kc is given below:
Where,
Kp is the pressure equilibrium constant
Kc is the molar equilibrium constant
R is gas constant
T is the temperature in Kelvins
Δn = (No. of moles of gaseous products)-(No. of moles of gaseous reactants)
For the first equilibrium reaction:
Given: Kc = 2.2
Temperature = 299 K
R = 0.082057 L atm.mol⁻¹K⁻¹
Δn = (2)-(2+1) = -1
Thus, Kp is:
<u>Kp = 0.08967 </u>
For the second equilibrium reaction:
Given: Kc = 2.3×10³⁰
Temperature = 299 K
R = 0.082057 L atm.mol⁻¹K⁻¹
Δn = (2)-(2) = 0
Thus, Kp is:
<u>Kp = 2.3×10³⁰</u>
