Answer:
Partial Pressure of F₂ = 1.30 atm
Partial pressure of Cl₂ = 0.70 atm
Explanation:
Partial pressure for gases are given by Daltons law.
Total pressure of a gas mixture = sum of the partial pressures of individual gases
Pt = P(f₂) + P(cl₂)
Partial pressure = mole fraction × total pressure
Let the mass of each gas present be m
Number of moles of F₂ = m/38 (molar mass of fluorine = 38 g/Lol
Number of moles of Cl₂ = m/71 (molar mass of Cl₂)
Mole fraction of F₂ = (m/38)/((m/38) + (m/71)) = 0.65
Mole fraction of Cl₂ = (m/71)/((m/38) + (m/71)) = 0.35 or just 1 - 0.65 = 0.35
Partial Pressure of F₂ = 0.65 × 2 = 1.30 atm
Partial pressure of Cl₂ = 0.35 × 2 = 0.70 atm
Answer:
In one rotation, the large wheel turns 4m.
Explanation:
The given values are:
Input distance,
= 0.64 m
Mechanical advantage,
= 0.16
As we know,
⇒ 
On putting the values, we get
⇒ 
⇒
Answer: 90.1 s
Explanation:
Use equation for power:
P=F*V
Use eqation for force:
F=ma
F---force
V---velocity
Vr=om/s
V=30m/s
m=1000kg
P=10000W
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P=FV
F=P/V
F=10000W/30m/s
F=333.33N
Use equation for force to find accelartaion.
F=ma
a=F/m
a=333.33N/1000kg
a=0.333 m/s²
Use equation for accelaration to find out time:
a=(V-Vs)/t
t=(V-Vs)/a
t=(30m/s)/(0.333m/s²)
t=90.09 s≈90.1 s
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The condition is a neuron in when the outside of the neuron has a net positive charge and the inside has a net negative charge (due to accumulation of more sodium ions) is C. resting potential. T<span>he </span>resting membrane<span> </span>potential<span> of a </span>neuron<span> is approximately -70 mV (mV=</span><span>millivolt)</span>
Passengers in an aircraft are subject to the Normal and Gravity Force acting on them at a low 'orbit', so tiny that it can be many times compared to the same surface of the earth when speaking in general terms.
In a high orbit space vehicle or in the same space, said force decreases considerably or simply disappears, generating the sensation of weightlessness.
Remember that the Force of Gravity is given under the principle

Where,
G = Gravitational Universal constant
M = Mass of the planet
m = mass of the object
r = Distance from center of the planet
When the radius grows considerably the gravitational force begins to decrease.