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castortr0y [4]
4 years ago
13

Momentum is what kind of quantity?

Physics
2 answers:
erastova [34]4 years ago
7 0

momentum = mass * volume

Kg * m / sec

aleksklad [387]4 years ago
3 0
It is a vector quantity
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A 69-kg student sitting on a hardwood floor does not slide until pulled by a 260-N horizontal force. find coefficient of frictio
salantis [7]

Answer:

μ = 0.385

Explanation:

Given that,

The mass of the student, m = 69 Kg

The horizontal force applied, F = 260 N

The normal force acting on the body, weight = mg = 69g  N

                                                                                    = 676.2 N

The coefficient of friction acting on a body is equal to the force acting on the body to the normal force acting on the body due to gravitation.

The formula for coefficient of friction,

                                    μ =  F / N

Substituting the values in the above equation,

                                     μ = 260 N / 676.2 N

                                        = 0.385

Hence, the  coefficient of friction, μ = 0.385

6 0
3 years ago
Each of the space shuttle's main engines is fed liquid hydrogen bya high-pressure pump. Turbine blades inside the pump rotateat
kvasek [131]

Answer:

a) a= \frac{4 \pi^2 (0.02 m)^2}{0.00162 s}=9.74 \frac{m}{s^2}

b) k = \frac{9.8}{9.74}=1.006

Explanation:

Part a

For this case we can begin finding the period like this:

T= \frac{1}{w} =\frac{1}{617 rad/s}=0.00162 s

Then we know that the centripetal acceleration is given by:

a= \frac{v^2}{r}

And the velocity is given by:

v=\frac{2\pi r}{T}

If we replace this into the acceleration we got:

a = \frac{(\frac{2\pi r}{T})^2}{r}= \frac{4 \pi^2 r}{T^2}

And we can replace the values and we got:

a= \frac{4 \pi^2 (0.02 m)^2}{0.00162 s}=9.74 \frac{m}{s^2}

Part b

For this case we want to find a value of k such that:

a= k 9.8

Where a = 9.74, so then we can solve for k like this:

k = \frac{9.8}{9.74}=1.006

8 0
3 years ago
1)
Reptile [31]

Answer:

the answer is C baseball and bowling ball

4 0
3 years ago
A 90kg woman and a 60kg boy are standing at rest on a frictionless frozen lake. The boy pushes the woman with a 40N horizontal f
uranmaximum [27]

Answer:

The acceleration of the woman is 0.44 m/s²

Explanation:

Given;

mass of the woman, m₁ = 90 kg

mass of the boy, m₂ = 60 kg

The force applied by the boy, f₂ = 40 N

The net horizontal force on the woman = 40 N

Apply Newton's second law of motion to determine the acceleration of the woman;

f = ma

a = f / m

a = 40 / 90

a = 0.44 m/s²

Therefore, the acceleration of the woman is 0.44 m/s²

6 0
3 years ago
Whats a good air time and maximum height
serg [7]

Answer: Time to reach max. height is the time taken by it to reach the topmost position whereas time of flight is the overall time taken by it, i.e. till it reach down back to the thrower or launcher. And also time of flight is double the time to reach maximum height.

Explanation:

5 0
3 years ago
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