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bekas [8.4K]
3 years ago
8

For a person with a Near Point (NP) = 45 cm, what would be his prescription's lens power = _________ diopters A) 1.08 diopters

B) 2.842105 diopters C) 1.778 diopters D) 0.54 diopters E) 0.225 diopters
Physics
1 answer:
natita [175]3 years ago
7 0

Answer:

The power of lens is 2.22 D.

Explanation:

Given that,

Distance of image v= 45 cm

We know that,

Distance of object u= ∞

Power of lens is the reciprocal of focal length.

P=\dfrac{1}{f}

We need to calculate the power of lens

Using formula of lens

\dfrac{1}{f}=\dfrac{1}{v}+\dfrac{1}{u}

Where, f = focal length

v = image distance

u = object distance

Put the value into the formula

\dfrac{1}{f}=\dfrac{1}{45}+\dfrac{1}{\infty}

\dfrac{1}{f}=\dfrac{1}{0.45}+0

P=\dfrac{1}{f}=2.22

Hence, The power of lens is 2.22 D.

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How long will it take a car to go from a complete stop to 44 m/s if they are
mafiozo [28]

Answer:

\boxed{\sf Time \ taken \ (t) = 8.8 \ s}

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Time taken (t)

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\sf \implies 44 = 0 + 5t \\  \\  \sf \implies 44 = 5t \\  \\  \sf \implies 5t = 44 \\  \\  \sf \implies t =  \frac{44}{5}  \\  \\  \sf \implies t = 8.8 \: s

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Answer:

Electric field, E=5.63\times 10^{16}\ N/C

Explanation:

Given that,

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