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AleksAgata [21]
2 years ago
11

Any help would be great!

Mathematics
1 answer:
Elina [12.6K]2 years ago
8 0

Answer:

g(x) = (x + 3)²

Step-by-step explanation:

the equation of a parabola in vertex form is

y = a(x - h)² + k

where (h, k ) are the coordinates of the vertex and a is a multiplier

here (h, k ) = ( - 3, 0 ) , then

g(x) = (x - (- 3))² + 0 , that is

g(x) = (x + 3)²

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Figure A

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Read 2 more answers
X +y=5, 3x-2y+5=0, this is the question​
Neko [114]

Step-by-step explanation:

x+y=5

3x-2y+5=0

3x-2y= -5

x+y=5...... equation 1

3x-2y= -5....... equation 2

there fore make x the subject of the formula in equation 1

x=5-y.. equation 3

substitute equation three in equation 2

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4 0
3 years ago
The sum of the squares of two consecutive positive integers is 41. Find the two
Komok [63]

We have to present the number 41 as the sum of two squares of consecutive positive integers.

1² = 1

2² = 4

3² = 9

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5² = 25

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<h3>Answer: 4 and 5</h3>

Other method:

n, n + 1 - two consecutive positive integers

The equation:

n² + (n + 1)² = 41     <em>use (a + b)² = a² + 2ab + b²</em>

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2n² + 2n + 1 = 41     <em>subtract 41 from both sides</em>

2n² + 2n - 40 = 0     <em>divide both sides by 2</em>

n² + n - 20 = 0

n² + 5n - 4n - 20= 0

n(n + 5) - 4(n + 5) = 0

(n + 5)(n - 4) = 0 ↔ n + 5 = 0 ∨ n - 4 =0

n = -5 < 0 ∨ n = 4 >0

n = 4

n + 1 = 4 + 1 = 5

<h3>Answer: 4 and 5.</h3>
7 0
3 years ago
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