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4 years ago

Find measure of angle 2

Mathematics

2 answers:

olya-2409 [2.1K]4 years ago

4 0

Answer: measure angle 2 is 72

Step-by-step explanation: All angles of a triangle add up to 180 so you add 42 and 30 to find measure angle 1 which would be 108 now a horizontal line is 180 is you subtract 108 from 180 and you get 72.

Anarel [89]4 years ago

3 0

Answer:

I am thinking 108 please correct me if I am wrong

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What is the approximate area of the shaded region in the figure below?

sveticcg [70]

Answer:

(a) 10.0 m²

Step-by-step explanation:

The radius of the inner circle is (2 m -1.1 m) = 0.9 m. The area of each circle is given by the formula ...

A = πr²

so, the difference in areas is ...

shaded = π(2 m)² -π(0.9 m)² = π(4 -0.81) m²

shaded area ≈ 10.0 m²

3 0

3 years ago

Is this a function or no?

zimovet [89]

Function

It is a function

6 0

3 years ago

The number of motor vehicles registered in millions in the US has grown as follows:

zysi [14]

Answer:

a) Figure attached

b) $r=\frac{n(\sum xy)-(\sum x)(\sum y)}{\sqrt{[n\sum x^2 -(\sum x)^2][n\sum y^2 -(\sum y)^2]}}$

For our case we have this:

n=10 $\sum x = 75.819, \sum y = 43.5231, \sum xy = 330.0321, \sum x^2 =574.8598, \sum y^2 =192.8274$

$r=\frac{10(330.0321)-(75.81948)(43.5231)}{\sqrt{[10(574.8598) -(75.819)^2][10(192.8274) -(43.5231)^2]}}=0.989$

So then the correlation coefficient would be r =0.989

Step-by-step explanation:

Previous concepts

The correlation coefficient is a "statistical measure that calculates the strength of the relationship between the relative movements of two variables". It's denoted by r and its always between -1 and 1.

Solution to the problem

Part a

Year (x): 1940, 1945 1950, 1955, 1960, 1965, 1970, 1975, 1980, 1985

Vehicles (Y): 32.4, 31.0, 49.2, 62.7, 73.9, 90.4, 108.4, 132.9, 155.8, 171.7

After apply natural log for the two variables and create the scatterplot in excel we got the following result on the figure attached.

Part b

And in order to calculate the correlation coefficient we can use this formula:

$r=\frac{n(\sum xy)-(\sum x)(\sum y)}{\sqrt{[n\sum x^2 -(\sum x)^2][n\sum y^2 -(\sum y)^2]}}$

For our case we have this:

n=10 $\sum x = 75.819, \sum y = 43.5231, \sum xy = 330.0321, \sum x^2 =574.8598, \sum y^2 =192.8274$

$r=\frac{10(330.0321)-(75.81948)(43.5231)}{\sqrt{[10(574.8598) -(75.81948)^2][10(192.8274) -(43.5231)^2]}}=0.989$